Prabal Baishya
Member
When I used 2-look PLL, what I used to do is-
After orienting LL, try to find a set of headlights on one side( headlight-2 corners stickers with same color on same layer).
If headlights are present, then put them on the back and do the A perm( A perm- x R' U R' D2 R U' R' D2 R2 x')
If you don't find any headlights then do the A perm from any side. Once you have headlights after that do the step again.
Once you have headlights everywhere then you will have these 4 cases-
Ua
(R U' R U) (R U) (R U') (R' U' R2) This is just a simple 3-edge cycle. It is almost as fast as the corner cycles. I solve this case with the bar at the front or the back.
Ub
(R2 U) (R U R' U') (R' U') (R' U R') This is the inverse of the other U perm. I place my hands slightly differently for this algorithm. I solve this case with the bar at the front or the back.
H
(M2' U) (M2' U2) (M2' U) M2' This is extremely easy to recognize and can be performed VERY quickly. The M'2 is actually performed as (M'M') with rapid pushing at the back face of the M layer with the ring and then middle fingers.
Z
(M2' U) (M2' U) (M' U2) (M2' U2) (M' U2) The Z permutation is performed very similarly to the H perm. The last U2 is not necessary if you account for it before the algorithm.
After orienting LL, try to find a set of headlights on one side( headlight-2 corners stickers with same color on same layer).
If headlights are present, then put them on the back and do the A perm( A perm- x R' U R' D2 R U' R' D2 R2 x')
If you don't find any headlights then do the A perm from any side. Once you have headlights after that do the step again.
Once you have headlights everywhere then you will have these 4 cases-
Ua
Ub
H
Z