DemonicCuberad
Member
Whats The Chance of getting an OLL+PLL skip normally after completing F2L.(do you need VCS?)
You mean a last layer skip?Whats The Chance of getting an OLL+PLL skip normally after completing F2L.(do you need VCS?)
I mean yeah. OLL+PLL Skip
There are 2^4 = 16 possible ways of assembling the last layer edges, if we look at only the edge orientation. Only 8 of these 16 ways will be solvable (since you can't have an odd number of bad edges), and if you don't do any LL influencing when solving F2L (but you should), the 8 solvable ways will show up equally frequently. These 8 solvable ways are (imagine "x" is the last layer colour):I dare say this has been asked many times here before, but I can't seem to ask the right search questions...
What are the probabilities of the dot, 'L', bar & and cross after finishing F2L? The 'L' seems most common...
. x .
x x x
. x .
(cross)
. x .
x x .
. . .
(L)
. x .
. x x
. . .
(L)
. x .
. x .
. x .
(bar)
. . .
x x x
. . .
(bar)
. . .
x x .
. x .
(L)
. . .
. x x
. x .
(L)
. . .
. x .
. . .
(dot)
Legit curious about how in the world you got those numbers.I might be wrong but
Cross=5/30
L=12/30
Bar=8/30
Dot=5/30
There are 2^4 = 16 possible ways of assembling the last layer edges, if we look at only the edge orientation. Only 8 of these 16 ways will be solvable (since you can't have an odd number of bad edges), and if you don't do any LL influencing when solving F2L (but you should), the 8 solvable ways will show up equally frequently. These 8 solvable ways are (imagine "x" is the last layer colour):
Code:. x . x x x . x . (cross) . x . x x . . . . (L) . x . . x x . . . (L) . x . . x . . x . (bar) . . . x x x . . . (bar) . . . x x . . x . (L) . . . . x x . x . (L) . . . . x . . . . (dot)
Thus the probabilities are:
Cross: 1/8
Dot: 1/8
Bar: 2/8 = 1/4
L: 4/8 = 1/2
Thanks for that - now I feel foolish that the calculation was so simple.
That's called an LL skip, and the probability is 1 / 15552. Also this is a really widely-posted probability, make sure you do your research before asking a question
30 ELL cases, 5 cross, 5 dot, 12 L and 8 BarLegit curious about how in the world you got those numbers.
What is the chance of getting a last layer skip? Also, has anybody gotten one? Just wondering.
okayyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy that might be a little hard to depend on during solves.Search before asking a question. In this case, it was literally 3 posts ago
But dot case can be avoided pretty much all the time as explained in one of @Owen Morrison 's videos.There are 2^4 = 16 possible ways of assembling the last layer edges, if we look at only the edge orientation. Only 8 of these 16 ways will be solvable (since you can't have an odd number of bad edges), and if you don't do any LL influencing when solving F2L (but you should), the 8 solvable ways will show up equally frequently. These 8 solvable ways are (imagine "x" is the last layer colour):
Code:. x . x x x . x . (cross) . x . x x . . . . (L) . x . . x x . . . (L) . x . . x . . x . (bar) . . . x x x . . . (bar) . . . x x . . x . (L) . . . . x x . x . (L) . . . . x . . . . (dot)
Thus the probabilities are:
Cross: 1/8
Dot: 1/8
Bar: 2/8 = 1/4
L: 4/8 = 1/2
Legit curious about how in the world you got those numbers.
That chances of you already getting one is about 1/15okayyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy that might be a little hard to depend on during solves.
I have done 1300 recorded solves and i haven't ever gotten one. I thought i was unlucky but i guess im "normally lucky"
What is the chance of getting an EPLL skip with petrus?
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