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I asked in the probability thread the probability of having a WV case at last slot , and the answer turned out to be about 1/150.
But in practice, since a lot of f2l algs involve an (R U' R') insert at the end, I'd imagine that WV would actually appear more than 1/150 of the time.

So when actually solving, does WV appear a decent amount in cases where it is justified to use it? Like at least 1/50 chance?

I asked in the probability thread the probability of having a WV case at last slot , and the answer turned out to be about 1/150.
But in practice, since a lot of f2l algs involve an (R U' R') insert at the end, I'd imagine that WV would actually appear more than 1/150 of the time.

So when actually solving, does WV appear a decent amount in cases where it is justified to use it? Like at least 1/50 chance?

What are the chances of skipping PLL on a 2x2? I just got a 9.65 seconds for the first time, and part of it was no PLL except for turning the top layer one turn, which I don’t personally count as PLL. And, regardless of wether I mix the cube or the computer scrambles, I end up skipping the PLL quite often, I would think about 1/10 or more of the time. Is there a mathematical way to determine this?

What are the chances of skipping PLL on a 2x2? I just got a 9.65 seconds for the first time, and part of it was no PLL except for turning the top layer one turn, which I don’t personally count as PLL. And, regardless of wether I mix the cube or the computer scrambles, I end up skipping the PLL quite often, I would think about 1/10 or more of the time. Is there a mathematical way to determine this?

The corners when oriented can be arranged in 24 ways (4 places for the first corner times 3 places for the second times 2 places for the third and 1 for the last.) Considering all 4 possible AUFs brings it down to 6 (24/4).
Out of six possible arrangements, 4 are Adjacent, 1 is diagonal, and 1 is solved. Therefore the odds of a PLL skip are 1/6.

Ooohhhh, that makes sense, thanks! Yeah, that’s about what I’m seeing. Most of the time I have to do the adjacent perm, and the other two cases (diagonal and already solved) seem to be about equal. Now I know why!

What are the chances of someone getting a world record average on 3x3 with the ZZ method? I think there is a 1/3 chances if people start using the method.

What are the chances of someone getting a world record average on 3x3 with the ZZ method? I think there is a 1/3 chances if people start using the method.