Robert-Y
Member
I'm also now colour neutral with this method. I'll sorta show you how you can become colour neutral easily with method (if you're already CN on 333). You just need to be CN at centres and know your pairs of opposite colours. In the following examples, I will be solving a cube which uses the "western" colour scheme. So white is opposite to yellow, orange is opposite to red and green is opposite to blue. Please scramble your cube in each example with white on top and green on front.
Example 1
Scramble: L' Rw2 R' B' F R Fw L' R D' Rw Uw' L' Rw2 R U2 B' Fw' F2 L Rw2 R' Uw' U' L R U2 Fw L B Uw' U2 R' B' Fw F Uw2 R2 U' R'
First two centres and 3 cross dedges
First two centres (green and blue):
U Lw' U x' U' Lw z B2 Lw2 z' Rw U2 Rw'
1st cross dedge (blue-white)
z' U F' Rw2 F
2nd cross dedge (blue-orange)
L' B' L2 Lw' U'
I have placed the blue-orange cross dedge next to the blue-white because I know that orange and white aren't opposite to each other. Do not worry if blue-orange should be on the other side of blue-white, you can correct that later. I do not bother to work out where blue-orange should be really be, in relation to blue-white because my recognition isn't that great, but I only "waste" 2 moves on average if it's in the wrong place I think. This system should always work.
3rd cross dedge (blue-red)
L Rw2 B
I know that red is opposite to orange, so I placed the blue-red dedge opposite to blue-orange.
Last 4 centres:
Yellow:
U l' Rw' U Rw
Orange:
U' Rw2 U Rw2' L x U' l' U l
White and Red:
Rw' U' Rw L' x' R (preserve the blue-yellow cross edge) U' Rw U2 Rw'
Pair up the last cross dedge and place it + pair up two other dedges and leave them in the BL and BR slots.
Ok, here I have a special case. Because I already paired up the blue-yellow dedge through preserving it whilst I solving the last 4 centres, I will place the blue-yellow dedge, hence finishing the cross, before I pair up two other dedges.
R' U L' F' L2 F
I have realised from inspecting the centres (which I assumed to be correct) that my cross has gone wrong slightly. However, like I mentioned before, this problem can be solved easily. I simply replaced blue-white with blue-yellow, did L2, and then placed blue-white in the correct position. Now my cross is complete.
Pair up two dedges and leave them in the BL and BR slots:
z' Uw' U R U' R' (red-white)
y2 L' U' L Uw (orange-yellow)
What I have done is, I did a double layer turn (Uw') and replaced two edges in the E layer so that when I slice back (i.e. when I do Uw), two dedges will be solved.
Finish pairing up the remaining edges using Hardwick's 2 pair chain solving method
Green-orange:
L' R U' L R' Uw'
The edges which were in FL and FR are (personally) slightly annoying to pair up when they are not the last 2 sets of edges to pair up. So I decided to just replace both them with other edges which can be easily paired up by doing a double layer turn.
Green-red:
R U R' Uw
I replaced the green-orange dedge with the partner of the green-red edge (in the FLd slot) so that when I slice back (by doing Uw) the green-orange dedge will not be affected and the green-red edges will be paired up.
Green-white:
L' U' L Dw
Replace with any "bad" dedge in the top layer and immediately pair up the white-orange edges:
R U R' Dw2
I could see that after the green-white edges the only edges that could be paired up by doing a double layer turn is white-orange, so I decided to move green-white out of the way and replace it with a "bad" dedge.
Green-yellow and red-yellow:
y' R U R' Uw.
Finish! (now for the remaining 333 part)
Example 2
Scramble: Rw2 D U B F2 D2 Uw U' L2 Fw D' Uw2 U2 Fw2 Uw' Fw2 D' Uw U' Rw2 Fw2 F Uw' B2 Rw' R' B2 L' Rw' F' Rw' R D' Uw2 U' B' Fw F D2 R
First two centres and 3 cross dedges
First two centres (white and yellow):
x' Dw' U' Rw' U' Rw' x' y Lw' U' Lw z' B Rw2 z Rw U2 Rw'
1st cross dedge (yellow-red)
z' D Rw U
2nd cross dedge (yellow-green)
L Rw U Rw' D'
I have placed the yellow-green cross dedge next to the yellow-red because I know that red and green aren't opposite to each other. Do not worry if yellow-green should be on the other side of yellow-red, you can correct that later.
3rd cross dedge (yellow-orange)
L F Rw U'
I know that orange is opposite to red, so I placed the yellow-orange dedge opposite to yellow-red.
Last 4 centres:
Orange:
L' U l2 U' Rw2
Blue:
U' Rw U2 Rw' L' x' U2 l2 U l2
Green and Red:
U' l' U Rw
Pair up the last cross dedge and place it + pair up two other dedges and leave them in the BL and BR slots.
To do this, I first leave half of the last cross dedge in the E layer and the other half on top.
z' L'
Ok, now this part gets a bit complicated but if you practise a bit, I hope you will be able to see why it works all the time.
So now I have half of the last cross dedge in the middle layer and the other half on top.
Dw'
This is a funny rule which I always follow. Because the half of the last cross dedge in FRd is facing the right, I will push it away from me, as though I were pushing the cross colour sticker itself. So if it was facing the front, then I would do Dw instead. And if it's in FLu and facing the front, I would do Uw'. Basically, you do a double layer turn which corresponds to where the cross colour sticker of the last cross edge in the E layer is facing.
Yellow-blue:
R U2 R'
I insert the other last cross edge in the FRu slot so that when I do Uw/Dw the centres will be restored and the last cross edges will be paired up and ready for placement.
Now I look at the other edge which is next to the last cross edge which I just inserted into FRu. The edge is green and orange. So I find its partner and place it in next slot (BRu) so that when I do Uw/Dw the centres will be restored and the last cross edges will be paired up and ready for placement, as well as these edges I will pair up.
Green-orange:
y2 L' U2 L
Similar to the above, I find the other blue-red edge and place it in FRu.
Blue-red:
R U2 R'
Now I can restore centres and finish the cross, leaving two "good" dedges in BL and BR.
Uw z' R' U R2 U' R2' z y
I have realised from inspecting the centres (which I assumed to be correct) that my cross has gone wrong slightly. However, like I mentioned before, this problem can be solved easily. I simply replaced yellow-green with yellow-blue, did R2, and then placed yellow-green in the correct position.
Finish pairing up the remaining edges using Hardwick's 2 pair chain solving method
Green-white:
R U R' Uw'
White-orange:
y L' U2 L Uw
White-blue:
y' U' L' U L Uw
Blue-orange:
L' U' L Uw'
White-red and green-red:
L' U L Uw L' U' L F' L F L' Uw'
Finish! (now for the remaining 333 part)
I might make 1 or 2 more examples, but for now, I think these examples are good enough.
Example 1
Scramble: L' Rw2 R' B' F R Fw L' R D' Rw Uw' L' Rw2 R U2 B' Fw' F2 L Rw2 R' Uw' U' L R U2 Fw L B Uw' U2 R' B' Fw F Uw2 R2 U' R'
First two centres and 3 cross dedges
First two centres (green and blue):
U Lw' U x' U' Lw z B2 Lw2 z' Rw U2 Rw'
1st cross dedge (blue-white)
z' U F' Rw2 F
2nd cross dedge (blue-orange)
L' B' L2 Lw' U'
I have placed the blue-orange cross dedge next to the blue-white because I know that orange and white aren't opposite to each other. Do not worry if blue-orange should be on the other side of blue-white, you can correct that later. I do not bother to work out where blue-orange should be really be, in relation to blue-white because my recognition isn't that great, but I only "waste" 2 moves on average if it's in the wrong place I think. This system should always work.
3rd cross dedge (blue-red)
L Rw2 B
I know that red is opposite to orange, so I placed the blue-red dedge opposite to blue-orange.
Last 4 centres:
Yellow:
U l' Rw' U Rw
Orange:
U' Rw2 U Rw2' L x U' l' U l
White and Red:
Rw' U' Rw L' x' R (preserve the blue-yellow cross edge) U' Rw U2 Rw'
Pair up the last cross dedge and place it + pair up two other dedges and leave them in the BL and BR slots.
Ok, here I have a special case. Because I already paired up the blue-yellow dedge through preserving it whilst I solving the last 4 centres, I will place the blue-yellow dedge, hence finishing the cross, before I pair up two other dedges.
R' U L' F' L2 F
I have realised from inspecting the centres (which I assumed to be correct) that my cross has gone wrong slightly. However, like I mentioned before, this problem can be solved easily. I simply replaced blue-white with blue-yellow, did L2, and then placed blue-white in the correct position. Now my cross is complete.
Pair up two dedges and leave them in the BL and BR slots:
z' Uw' U R U' R' (red-white)
y2 L' U' L Uw (orange-yellow)
What I have done is, I did a double layer turn (Uw') and replaced two edges in the E layer so that when I slice back (i.e. when I do Uw), two dedges will be solved.
Finish pairing up the remaining edges using Hardwick's 2 pair chain solving method
Green-orange:
L' R U' L R' Uw'
The edges which were in FL and FR are (personally) slightly annoying to pair up when they are not the last 2 sets of edges to pair up. So I decided to just replace both them with other edges which can be easily paired up by doing a double layer turn.
Green-red:
R U R' Uw
I replaced the green-orange dedge with the partner of the green-red edge (in the FLd slot) so that when I slice back (by doing Uw) the green-orange dedge will not be affected and the green-red edges will be paired up.
Green-white:
L' U' L Dw
Replace with any "bad" dedge in the top layer and immediately pair up the white-orange edges:
R U R' Dw2
I could see that after the green-white edges the only edges that could be paired up by doing a double layer turn is white-orange, so I decided to move green-white out of the way and replace it with a "bad" dedge.
Green-yellow and red-yellow:
y' R U R' Uw.
Finish! (now for the remaining 333 part)
Example 2
Scramble: Rw2 D U B F2 D2 Uw U' L2 Fw D' Uw2 U2 Fw2 Uw' Fw2 D' Uw U' Rw2 Fw2 F Uw' B2 Rw' R' B2 L' Rw' F' Rw' R D' Uw2 U' B' Fw F D2 R
First two centres and 3 cross dedges
First two centres (white and yellow):
x' Dw' U' Rw' U' Rw' x' y Lw' U' Lw z' B Rw2 z Rw U2 Rw'
1st cross dedge (yellow-red)
z' D Rw U
2nd cross dedge (yellow-green)
L Rw U Rw' D'
I have placed the yellow-green cross dedge next to the yellow-red because I know that red and green aren't opposite to each other. Do not worry if yellow-green should be on the other side of yellow-red, you can correct that later.
3rd cross dedge (yellow-orange)
L F Rw U'
I know that orange is opposite to red, so I placed the yellow-orange dedge opposite to yellow-red.
Last 4 centres:
Orange:
L' U l2 U' Rw2
Blue:
U' Rw U2 Rw' L' x' U2 l2 U l2
Green and Red:
U' l' U Rw
Pair up the last cross dedge and place it + pair up two other dedges and leave them in the BL and BR slots.
To do this, I first leave half of the last cross dedge in the E layer and the other half on top.
z' L'
Ok, now this part gets a bit complicated but if you practise a bit, I hope you will be able to see why it works all the time.
So now I have half of the last cross dedge in the middle layer and the other half on top.
Dw'
This is a funny rule which I always follow. Because the half of the last cross dedge in FRd is facing the right, I will push it away from me, as though I were pushing the cross colour sticker itself. So if it was facing the front, then I would do Dw instead. And if it's in FLu and facing the front, I would do Uw'. Basically, you do a double layer turn which corresponds to where the cross colour sticker of the last cross edge in the E layer is facing.
Yellow-blue:
R U2 R'
I insert the other last cross edge in the FRu slot so that when I do Uw/Dw the centres will be restored and the last cross edges will be paired up and ready for placement.
Now I look at the other edge which is next to the last cross edge which I just inserted into FRu. The edge is green and orange. So I find its partner and place it in next slot (BRu) so that when I do Uw/Dw the centres will be restored and the last cross edges will be paired up and ready for placement, as well as these edges I will pair up.
Green-orange:
y2 L' U2 L
Similar to the above, I find the other blue-red edge and place it in FRu.
Blue-red:
R U2 R'
Now I can restore centres and finish the cross, leaving two "good" dedges in BL and BR.
Uw z' R' U R2 U' R2' z y
I have realised from inspecting the centres (which I assumed to be correct) that my cross has gone wrong slightly. However, like I mentioned before, this problem can be solved easily. I simply replaced yellow-green with yellow-blue, did R2, and then placed yellow-green in the correct position.
Finish pairing up the remaining edges using Hardwick's 2 pair chain solving method
Green-white:
R U R' Uw'
White-orange:
y L' U2 L Uw
White-blue:
y' U' L' U L Uw
Blue-orange:
L' U' L Uw'
White-red and green-red:
L' U L Uw L' U' L F' L F L' Uw'
Finish! (now for the remaining 333 part)
I might make 1 or 2 more examples, but for now, I think these examples are good enough.
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