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Skyler Variation (SV)

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jskyler91

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its ok. you don't need to lie.
Umm... ok, not sure if your joking here, but I mean what I say so its up to you to decide if you believe me. I have to reason to lie about this. The effort of writing these posts and generating these algs greatly outweighs any possible gain from the popularity of having your own method.

It's like how chance of getting a specific PLL isn't 1/22.



How?!
It seems that at least half of the cases will allow me to setup into these cases in less moves than if I just solved them so I would at least have over a 50% chance of doing these cases. I did think the 94 percent was rather high though lol.

Also, I never understood why it wasn't the case that you didn't have a 1/21 chance of each pll. Could you explain that?
 
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Kirjava

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It seems that at least half of the cases will allow me to setup into these cases in less moves than if I just solved them so I would at least have over a 50% chance of doing these cases.
If you're having trouble understanding what I'm saying, please do not continue to post things that contradict it.

Mathematically, there are not 42 last slot cases.
 

jskyler91

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If you're having trouble understanding what I'm saying, please do not continue to post things that contradict it.

Mathematically, there are not 42 last slot cases.
I understand that, but since you have yet to provide me with the actual number of cases I am going with the only approximate I have which is 42 cases. If you exclude mirrors, AUFs and that type of stuff which are just basically the same thing, you only really have 42 cases, particularly for the last slot. Also, you said 20 was less than half of 42 and so I went with that.
 
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aronpm

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I understand that, but since you have yet to provide me with the actual number of cases I am going with the only approximate I have which is 42 cases. If you exclude mirrors, AUFs and that type of stuff which are just basically the same thing, you only really have 42 cases. Also, you said 20 was less than half of 42 and so I went with that.
There are much more cases than 42; you have given no justification for an approximation of 42 for the total # of cases. Also, solved is a completely normal case and you do NOT exclude it while calculating.
 

Kirjava

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I understand that, but since you have yet to provide me with the actual number of cases I am going with the only approximate I have which is 42 cases. Also, you said 20 was less than half of 42 and so I went with that.
42 is not an approximation. You're putting random numbers into your calculations.
 

jskyler91

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This is an interesting approach I think, what held me from learning many of the other variations is that extra look...

The "Problem" of this approach ist the enourmous number of algorithms. But I've decided what to do (for me).

I will start by learning the cases for the flipped edge and the correct corner first:


Thats because of three reasons:
1. I hate this case, when it comes up I know I'll need more time to get finished.
2. It is extremely easy to spot. (if not the easiest case to spot)
3. If you learn the algs for this case first, you can also use them in another way (aka use them more often/more easier than the other cases):
Everytime the case pops up (and not only as last F2L pair but also in F2l in general) I'll get free OLL.
If it pops up as one of the first three F2l Pairs, I would just continue solving the others pairs in a correct way and then get back to the slot to do the algorithm.


I've not yet decided to learn the other algorithms, because they are a ton. But I thank you in advance for the 27algs to kill my most hatred case ;-)
I hope they help you, also if you find an alg that absolute sucks feel free to find another and post it here. Some of the cases aren't that great and I wasn't so amazing at finding algs at first so I might have missed a few good ones.

There are much more cases than 42; you have given no justification for an approximation of 42 for the total # of cases. Also, solved is a completely normal case and you do NOT exclude it while calculating.
I am not going to claim to know the answer to this question,nor am I going to try and figure it our. All I was saying is that if we are just talking about LS then 42 sounds about right. Sure there are like 4 positions for the AUF, but if you had the alg AUFed it would be 42 right? what other cases am I missing assuming all 3 slots are filled?
 
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jskyler91

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How many times do we have to say that it is not 42 before you give up thinking that it is 42?
Please either provide me the actual number, a way of finding the number or stop wasting space on my thread. The point i am trying to make is that you have a large chance of getting these cases. If I am wrong then please provide mathematical proof that I am. If not then you are willingly trying to antagonize me and wasting space, both of which are against the forum rules:

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Also I am posting this per request of the sites rules as listed here:

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aronpm

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If I am wrong then please provide mathematical proof that I am.
total cases for 1,2,3,4 open slots: 150, 216, 294, 384
n open slots has n+4 corners, n+4 edges, so (n+4)(n+4)*3*2=6(n+4)^2 cases

I've been told that the probability of getting 4 move insertion for SV in LS is 41%, 28% for 2 slots, 21% for 3 slots and 16% for 4 slots. Probability of not getting SV = (1-.41)*(1-.28)*(1-.21)*(1-.16)=.28, so probability of getting at least 1 SV is 72%
 

jskyler91

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total cases for 1,2,3,4 open slots: 150, 216, 294, 384
n open slots has n+4 corners, n+4 edges, so (n+4)(n+4)*3*2=6(n+4)^2 cases

I've been told that the probability of getting 4 move insertion for SV in LS is 41%, 28% for 2 slots, 21% for 3 slots and 16% for 4 slots. Probability of not getting SV = (1-.41)*(1-.28)*(1-.21)*(1-.16)=.28, so probability of getting at least 1 SV is 72%
Cool thanks a lot man!!! so 72 % if you include every case possible and a 4 move insert, higher chances if you only du 3 move inserts right?
 

Stefan

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I just checked one example solve (scramble L2 R2 F2 L' D2 U F2 D' B F R B2 F2 R U F' L2 R' D' L R2 D' U' L F) and one alg on your alg sheets (first alg on first sheet, starting with R2 U2 R2) and both didn't work. Very disappointing. Please make sure your solutions/algs are correct. I recommend alg.garron.us, same that Brest uses for his reconstructions. And when you do that, you'll have to use standard notation (e.g. y, not Y).

You call it a last slot method, have you considered missolving an earlier slot (perhaps even for xcross) instead of the last one?

You still haven't removed that duplicate case that I mentioned earlier.
 

Godmil

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Thanks for the example solves, I went through from your cross till end of OLL and found my solutions had 3 less moves in the first one, 4 less moves in the second one, but 8 more moves in the 3rd one. Overall I guess it balances out. Your third solution was pretty awesome, but I'm not convinced overall, it seems to just make 1 F2L case a little shorter, and the OLL a little longer. Though it will be really interesting to see how you get on if you make it your main method.
 
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jskyler91

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I just checked one example solve (scramble L2 R2 F2 L' D2 U F2 D' B F R B2 F2 R U F' L2 R' D' L R2 D' U' L F) and one alg on your alg sheets (first alg on first sheet, starting with R2 U2 R2) and both didn't work. Very disappointing. Please make sure your solutions/algs are correct. I recommend alg.garron.us, same that Brest uses for his reconstructions. And when you do that, you'll have to use standard notation (e.g. y, not Y).

You call it a last slot method, have you considered missolving an earlier slot (perhaps even for xcross) instead of the last one?

You still haven't removed that duplicate case that I mentioned earlier.
I did my a few examples of it not being a last slot in the example solves. Also, I know it sounds rude, but make sure you scrambled right because I checked the solutions many times. Which duplicate was it? I thought I removed it.
 

jskyler91

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Thanks for the example solves, I went through from your cross till end of OLL and found my solutions had 3 less moves in the first one, 4 less moves in the second one, but 8 more moves in the 3rd one. Overall I guess it balances out.
Interesting, can you post your solves for the first two? also I do things that take more moves but are quicker in execution so keep that in mind, I could have made my movecount much lower, but that was not how I would have solved so I was true to myself.
 

Stefan

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Which duplicate was it? I thought I removed it.
These are the cases which setup into Skyler Variation with a URU'R':
First and last are the same.

I know it sounds rude, but make sure you scrambled right because I checked the solutions many times.
Doesn't work.
 
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