CxLL T F

T F

This case and the case U F are inverses of each other so the same algorithm (9 move commutator or mirror) can be used to solve both.

---

As for all T cases you look at two "bars" of stickers, one at Fur-Ful and one at Urb-Ulb. In this case the bar at Ub has got one colour and the bar at the F-side has got two opposite colours.

COLL

• (y2 x') U' R2 U' L2 U R2 U' L2 U2 (x)
• (y') l' U2 R' D2 R U2 R' D2 R2 (x')
• F U' r' F R2 F' r U R2 F'
• (U) F' R' F U2 F' R F R' U2 R
• (U2) F R U R' U' R U' R' U' R U R' F'

CLL

• (U) r U2 r F2 r' U2 r F2 r2

CMLL

• ...

CLLEF

• y2 R B' R' B y U2 R U2 B2 L' B' L B' R'

CF / 2x2x2 (Waterman)

• ...

EG

EG 2 --> 2x2x2

EG 1

• ...

EG 0

• ...

Navigator

CxLL edit	U	D	R	L	F	B
U	U U	U D	U R	U L	U F	U B
T	T U	T D	T R	T L	T F	T B
L	L U	L D	L R	L L	L F	L B
S	S U	S D	S R	S L	S F	S B
-S	-S U	-S D	-S R	-S L	-S F	-S B
Pi	Pi U	Pi D	Pi R	Pi L	Pi F	Pi B
H	H U	H D	H R	H L	H F	H B

Hyper CLL edit	U	D	R	L	F	B
U	U U	U D	U R	U L	U F	U B
T	T U	T D	T R	T L	T F	T B
L	L U	L D	L R	L L	L F	L B
S	S U	S D	S R	S L	S F	S B
-S	-S U	-S D	-S R	-S L	-S F	-S B
Pi	Pi U	Pi D	Pi R	Pi L	Pi F	Pi B
H	H U	H D	H R	H L	H F	H B