CxLL L L
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L L
The four cases, U R, U L, L L and L F are mirrors and inverses of each other so the same algorithm (9 move commutator) can be used to solve them all.
First look in the U-face, there are two stickers of the same colour, next find the two stickers of the opposite colour. Case L F looks the same but mirrored. |
COLL
- (y) R U2 R D R' U2 R D' R2
CLL
- ...
CMLL
- R U2 L' U' L U2 R' U R' F2 R
CLLEF
- y' R U R' U R' F R F' U2 R' F R F'
CF / 2x2x2 (Waterman)
- ...
EG
EG 2 --> 2x2x2
EG 1
- ...
EG 0
- y R'UR'F'U'FUF2R2
CxLL edit |
U |
D |
R |
L |
F |
B |
U |
U U |
U D |
U R |
U L |
U F |
U B |
T |
T U |
T D |
T R |
T L |
T F |
T B |
L |
L U |
L D |
L R |
L L |
L F |
L B |
S |
S U |
S D |
S R |
S L |
S F |
S B |
-S |
-S U |
-S D |
-S R |
-S L |
-S F |
-S B |
Pi |
Pi U |
Pi D |
Pi R |
Pi L |
Pi F |
Pi B |
H |
H U |
H D |
H R |
H L |
H F |
H B |
Hyper CLL edit |
U |
D |
R |
L |
F |
B |
U |
U U |
U D |
U R |
U L |
U F |
U B |
T |
T U |
T D |
T R |
T L |
T F |
T B |
L |
L U |
L D |
L R |
L L |
L F |
L B |
S |
S U |
S D |
S R |
S L |
S F |
S B |
-S |
-S U |
-S D |
-S R |
-S L |
-S F |
-S B |
Pi |
Pi U |
Pi D |
Pi R |
Pi L |
Pi F |
Pi B |
H |
H U |
H D |
H R |
H L |
H F |
H B |