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I wouldn't. Thats just understanding Pseudo Blocks and how to add premoves for that.

Normal Inverse Scramble Switch is more using your progress to completely switch from Normal to Inverse and vise versa.

Obviously switching after those first 5 moves will lead you to finding the 2move more to 2x2x3 but I found it more as directly just adding the premoves to solve the 2move Pseudo 2x2x3.

I figured out that after the first 5 moves switching the scramble (NISS) will get you more easily to that 16 move L3C.
And no corner-insertion is needed, just solve 3 corners subsequently and 5 moves cancel automatically .....
I wonder why no other competitor found this 19 move beauty..
(Sorry Marcel)

I figured out that after the first 5 moves switching the scramble (NISS) will get you more easily to that 16 move L3C.
And no corner-insertion is needed, just solve 3 corners subsequently and 5 moves cancel automatically .....
I wonder why no other competitor found this 19 move beauty..
(Sorry Marcel)

I figured out that after the first 5 moves switching the scramble (NISS) will get you more easily to that 16 move L3C.
And no corner-insertion is needed, just solve 3 corners subsequently and 5 moves cancel automatically .....
I wonder why no other competitor found this 19 move beauty..
(Sorry Marcel)

I figured out that after the first 5 moves switching the scramble (NISS) will get you more easily to that 16 move L3C.
And no corner-insertion is needed, just solve 3 corners subsequently and 5 moves cancel automatically .....
I wonder why no other competitor found this 19 move beauty..
(Sorry Marcel)

After I saw that an L Move on the Inverse creates a pseudo 1x2x3 block I switched to the normal scramble. Then my first linear solution was the 16 Move skeleton. I decided to insert the corners before switching again after the first 5 Moves.

When I was at home after the competition I looked again on my solution and found this 20 Move Solution with a similar start. Seems to be a very potential scramble:

Premove F' (1/1)
F2 L2 $ F' U F' U2 (6/7) - 2x2x3 + blocks
D L' D' (3/10) - EO
L' B L' B' L2 B2 (6/16) - L3E
$ = L2 F2 R2 U R2 F2 L2 D (8-4/20)

Solution: R2 U R2 F2 L2 D F' U F' U2 D L' D' L' B L' B' L2 B2 F' (20 Moves)