What puzzle do you think the WCA should add next?

I was thinking TeamBLD, but you'd have a lot of people shouting at the same time and it would get very confusing. You could also hear what other people are saying and learn information about a scramble before attempting it.

I doubt there would be any shouting. If you watch videos of people doing TeamBLD, communication is at a reasonable speaking volume.
 
I doubt there would be any shouting. If you watch videos of people doing TeamBLD, communication is at a reasonable speaking volume.
Well not quite shouting, but it could get quite loud. And some people could shout to be heard more. The videos of people doing TBLD don't usually have 10 other people trying to tell someone what to do at the same time.
 
I doubt there would be any shouting. If you watch videos of people doing TeamBLD, communication is at a reasonable speaking volume.

Even if shouting isnt a problem, recording the data to the wca is. How could you record the solutions to where?
 
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Well not quite shouting, but it could get quite loud. And some people could shout to be heard more. The videos of people doing TBLD don't usually have 10 other people trying to tell someone what to do at the same time.

It would be quite dumb to start shouting or speaking loudly....
Also: imho there are no restrictions on how to communicate. It would be funny if someone would develop a method where you just tap different body parts of the solver to indicate what he has to do ^^

Imho Team BLD is the only event that would really add a new dimension, instead of another twisty puzzle. It's fun, social and relatively easy to organize. Another positive thing is: there are a LOT of judges since one team of group A can judge 2 teams of group B ;-)
 
He wouldn't speedBLD in MBLD. No one would.

But you could use more efficient packing of information. Example: if you want to memorize permutations of the numbers 1 to 4, you can of course memorize it as four digits like "1432". But there are only 4!=24 possibilities, so you could instead encode the permutation as a number from 1 to 24. That's just one or two digits to memorize instead of four. Or one letter, if you prefer.

Similarly, you can memorize a 3x3 as a string of about 20 numbers from {1,...,24}. But 24^20 is about 4*10^27, about eight digits more than the number of actually possible cube states. So you're memorizing eight digits more than strictly necessary! You can for example break the cube state down into EP, CP, EO and CO and represent each of those with a number from 1 to 12!/2, 8!, 2^11 and 3^7, which would be 22 digits. Of course those numbers are still quite large, but for 2x2 some useful tighter packing might be possible.

Btw, Richard Carr worked on a method for solving 3x3 blindfolded in pretty much 4-5 algs: one alg each for EO, CP and CO and one or two for EP.
 
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