Waffle's Roux Tutorial

[waffle=ijm]

But I think it may be safe to say: No one who does roux as their main method, and who is very fast, is colour neutral?

Methinks correct.

 

[Hershey]

Do you read what you type before you post? Or do you headbang the keyboard until something comes out as a coherant sentence?

In case you don't understand, you're wrong.

Infract me if you wish, I'll take it like a man.

I did read before I posted. What was wrong when I said K4 starts like Roux but is more of a LBL type method? To take it even further, what have I done wrong? What makes me such a bad cuber and what makes you such a good cuber? Even if I did say something useful, you would probably still flame me.

 

[RyanReese09]

I did read before I posted. What was wrong when I said K4 starts like Roux but is more of a LBL type method? To take it even further, what have I done wrong? What makes me such a bad cuber and what makes you such a good cuber? Even if I did say something useful, you would probably still flame me.

You have 466 posts. I've probably flamed you 4 or 5 times. I'd go even as high as 10.

I see every post on this forum. *EVERY*. If I flamed every post of yours I'd have been banned permanently months ago. If you do K4 and end up with a LBL type method you're doing it completely wrong. I never said I was a better cuber, I just said you were wrong. Which you were.

 

[RyanReese09]

[21:34] <+RobertY> Quote of the day?: "K4 starts out like Roux, but the rest of the solve is more of a LBL or CFOP method."
[21:34] <+RobertY> by hershey
[21:34] <+RobertY> yeah it's like cfop
[21:34] <+RobertY> for people who are doing it compeltely wrong

Sorry Robert.

 

[Hershey]

[21:34] <+RobertY> Quote of the day?: "K4 starts out like Roux, but the rest of the solve is more of a LBL or CFOP method."
[21:34] <+RobertY> by hershey
[21:34] <+RobertY> yeah it's like cfop
[21:34] <+RobertY> for people who are doing it compeltely wrong

Sorry Robert.

Ok fine. It isn't like CFOP, but is it a LBL method? After the 1x3x4 and centers, you finish one layer, then finish the first 3 layers, then corners of the last layer, and lastly the edges.

 

[Athefre]

I have a 4c technique that I suggest Roux users try. I've been using it long enough now that I feel that it is a great solution for those annoying 3-cycles. It will result in you having zero pauses during LSE.

During 4b, near the end of placing UL and UR, watch the U/D color of one of the edges that goes to DF or DB. Now find the other of that color. It will be on U. Align that edge so that it is diagonal from the edge on D. Lastly, there will be an edge on U that doesn't match the U center. Bring it toward U using M or M' and do U2. Then you can finish the rest. It's difficult to explain with just words so here are a few examples:

U M2 U M2 U M U2 M' U2 M' U M2 U M2 U M' U M2 U2 M' U' M2 U M'

Solve: M'U'M' U...Now, see the sticker at UB? Remember the color and slot UL and UR with M2. Now that sticker is at DF. There is another unsolved edge on U that has that color. It is at UL. Do U to place it diagonally from DF. Then do M' to bring the unmatched U edge toward U, then U2. Finish with M.

U' M2 U' M U2 M' U' M2 U' M2 U' M2 U2 M' U' M U' M' U2 M' U' M2 U2

Solve: U'MUM'U2M'U2M' U'...Now remember the sticker at UB then do M2. It is now at DF. It's matching color is at UR. Place it diagonally from DF by doing U'. Since it doesn't match the U center, bring it toward U by doing M. Then do U2 and finish with M'.

U' M2 U' M' U2 M2 U' M' U2 M' U M' U2 M2 U2 M U2 M2 U2 M U M2 U M U M'

Solve: M2UM'UM' U'M2U...Before slotting the last UL/UR edge, look at the sticker at UB and remember it's color. Do M'U2M'. Now that sticker is at DF. The other color like it is at UR. Place it diagonally from DF by doing U'. The UF sticker doesn't match the U center. So do M' to bring it toward U. Then do U2 and finish with MU2.

For the bar cases (U2M2U2, E2M'E2), you'll know you have one of those before finishing 4b because you see the bar of matching colors on U. So continue to use whatever way you like for those cases.

 

[5BLD]

I have a 4c technique that I suggest Roux users try. I've been using it long enough now that I feel that it is a great solution for those annoying 3-cycles. It will result in you having zero pauses during LSE.

During 4b, near the end of placing UL and UR, watch the U/D color of one of the edges that goes to DF or DB. Now find the other of that color. It will be on U. Align that edge so that it is diagonal from the edge on D. Lastly, there will be an edge on U that doesn't match the U center. Bring it toward U using M or M' and do U2. Then you can finish the rest. It's difficult to explain with just words so here are a few examples:

U M2 U M2 U M U2 M' U2 M' U M2 U M2 U M' U M2 U2 M' U' M2 U M'

Solve: M'U'M' U...Now, see the sticker at UB? Remember the color and slot UL and UR with M2. Now that sticker is at DF. There is another unsolved edge on U that has that color. It is at UL. Do U to place it diagonally from DF. Then do M' to bring the unmatched U edge toward U, then U2. Finish with M.

U' M2 U' M U2 M' U' M2 U' M2 U' M2 U2 M' U' M U' M' U2 M' U' M2 U2

Solve: U'MUM'U2M'U2M' U'...Now remember the sticker at UB then do M2. It is now at DF. It's matching color is at UR. Place it diagonally from DF by doing U'. Since it doesn't match the U center, bring it toward U by doing M. Then do U2 and finish with M'.

U' M2 U' M' U2 M2 U' M' U2 M' U M' U2 M2 U2 M U2 M2 U2 M U M2 U M U M'

Solve: M2UM'UM' U'M2U...Before slotting the last UL/UR edge, look at the sticker at UB and remember it's color. Do M'U2M'. Now that sticker is at DF. The other color like it is at UR. Place it diagonally from DF by doing U'. The UF sticker doesn't match the U center. So do M' to bring it toward U. Then do U2 and finish with MU2.

For the bar cases (U2M2U2, E2M'E2), you'll know you have one of those before finishing 4b because you see the bar of matching colors on U. So continue to use whatever way you like for those cases.

Hm, interesting idea, but it will certainly cause a stumble for the E2ME2M and U2MU2M cases...
Most of us rouxers do this automatically anyway like auto-optimisation.

OT: Yup, I'm back and I don't care. I see an interesting post, I reply anyway. Go ahead, flame me. I just wanna see whether it's improved over, what, almost two months possibly?

 

[Athefre]

It doesn't cause any problems for U2M2U2 or E2M'E2. I've done about 5,000 solves using this. It works.

 

[5BLD]

It doesn't cause any problems for U2M2U2 or E2M'E2. I've done about 5,000 solves using this. It works.

Really? For me, it causes trouble because I usually look at FD to check and find the other edges through process of elimination...
Interesting how different rouxers solve...

EDIT:
How many sub-15 rouxers are there? I know it's asked alot but never properly answered...

 

[Cheese11]

Could you please make a tutorial on Roux for the 4x4?

I could do that if you would like. Just pm me on YouTube (EricKulchycki) and I'll make it.

 

[5BLD]

I could do that if you would like. Just pm me on YouTube (EricKulchycki) and I'll make it.

Out of interest, what's so different about roux for the 4x4 to the 3x3?

 

[Cool Frog]

lol. no one is color neutral on roux.

I am, But the thing is on how EASY it is to force different colors, I honestly don't think there is any advantage or disadvantage to it.
I usually just go with whatever seems easier, as long as I can plan the entire first block.

But why is that? It doesn't look like a particularly hard method to be colour neutral with, to be honest. Only the CMLL detection would mess you up, really. Or am I wrong (which is certainly possible)?

CMLL is rather easy, same recognition, different day

 

[5BLD]

I am, But the thing is on how EASY it is to force different colors, I honestly don't think there is any advantage or disadvantage to it.
I usually just go with whatever seems easier, as long as I can plan the entire first block.

CMLL is rather easy, same recognition, different day

Yeah, cmll is easy because its pattern recognition; instead of colour recognition.
And yeah, the reason why you find colour neutral so easy is because you recognise patterns of colours, whilst most of us look for, say, white stickers. I use the same colour scheme as waffo but sometimes go colour neutral if it's easy and then force yellow/white anyway... In fact, I DO go full colour neutral on the first block, then force white on bottom.

Also, you probably started colour neutral didn't you? I should've too; instead of using the CFOP colours =/

 

[pijok]

I have a 4c technique that I suggest Roux users try. I've been using it long enough now that I feel that it is a great solution for those annoying 3-cycles. It will result in you having zero pauses during LSE.

During 4b, near the end of placing UL and UR, watch the U/D color of one of the edges that goes to DF or DB. Now find the other of that color. It will be on U. Align that edge so that it is diagonal from the edge on D. Lastly, there will be an edge on U that doesn't match the U center. Bring it toward U using M or M' and do U2. Then you can finish the rest. [...]

Scramble: F2 M' F2 M U M2 (6STM)
How are you going to solve it?

 

[Athefre]

Scramble: F2 M' F2 M U M2 (6STM)
How are you going to solve it?

You found the one case that doesn't solve a 3-cycle as a 3-cycle. But it's also a case that really doesn't matter. It only adds one more move to that case, and that is made up for by not having recognition time.

So the solution is: M2UMU2MU2M2U2 compared to the old way of M2U'M2U2MU2M.

 

[uberCuber]

Also, you probably started colour neutral didn't you? I should've too; instead of using the CFOP colours =/

I think what you mean is your CFOP colors lulz. It's not like CFOP has set colors any more than Roux does.

 

[5BLD]

My bad. I meant the CFOP colours most CFOPers use... i.e. white on bottom. And yellow too.

As in the 'Roux colours' are white and yellow on L/R if you see what I mean.

Although- as you say, there are no set colours for any given method... I was referring to the way most people did it.

 

[Cheese11]

My bad. I meant the CFOP colours most CFOPers use... i.e. white on bottom. And yellow too.

As in the 'Roux colours' are white and yellow on L/R if you see what I mean.

Although- as you say, there are no set colours for any given method... I was referring to the way most people did it.

Ya, I solve Roux. My colours are white or yellow on the sides, and either orange or green on top.

 

[pijok]

You found the one case that doesn't solve a 3-cycle as a 3-cycle. But it's also a case that really doesn't matter. It only adds one more move to that case, and that is made up for by not having recognition time.

So the solution is: M2UMU2MU2M2U2 compared to the old way of M2U'M2U2MU2M.

yeah, thanks, it works well.
i'm going to use this method, it is very fast

 

[StachuK1992]

Ya, I solve Roux. My colours are white or yellow on the sides, and either orange or green on top.

Are orange/green opposites on your cube? Curious.