Brest
Moderator
I see what you did there, but a nice thing to do in a speedsolve is RUR'U2RUR'![]()
True that, but I saw the CE pair and made a square while inserting the last F2L pair.
Really, I should've gone for the other pair, as it was already setup to insert.
Next: B R2 U2 F B D2 U2 B L2 U2 R2 L' U2 L2 R' B U2 D F U' L' U F2 D' B'
inspection: x'z
cross: R2U'L2x'DLD
f2l1: L'ULU2L'UL
f2l2: yR'URU'R'U'R
f2l3: y'URUR2U'R
f2l4: d'L'U'L
oll+ep: l'U'LUlF'L'F
pll: xR'UR'D2'RU'R'D2'R2'
next: F' D R2 D2 B2 U2 L' D2 U R' F B' U2 L' R' U' R' L' F2 D' B D' L B' L'
oll+ep: l'U'LUlF'L'F
pll: xR'UR'D2'RU'R'D2'R2'
You had the edges solved here, so you could use a corner cycle.
The one you had here is basically a 'free' algorithm, as it's very similar to an A perm, just with double turns.
L' B2 L' F2 L B2 L' F2 L2
Next: D2 B' L2 U2 F U2 F' L2 B2 U2 R2 U R' U2 L' F' U' B2 D' R B
U B' R2 D F2 R' F L F' R F R' U B F' L2 F U L2 U L2 B2 R2 D R2 (25)
U B' [1st square]
R2 D F' [2nd square]
.L R' U':B U B2 [Leaving 3C5E]
B2 L2 U L2 B2 R2 D R2 [L3E]
.=F' R' F L F' R F L'
:=U2 B F' L2 B' F
Next: B R L U' L R2 B' U R2 U' R' L2 U D2 F2 D2 L' F2 D2 L U B' L R F'
So good! How do you do it...
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