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Square-1 Parity Algs

blade740

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blade740
Thread starter #21
I do that in a different way than I do on 3x3 though. I usually do it by looking at blocks. For example, if there is a CEC block, I know that there cannot be another block (except for a j perm) for it not to have parity.
I'm not sure if you're mistaken or just disregarding a horrible parity case.

Dene said:
For example, I have particular trouble distinguishing E perm from what I will call "E parity"; I have to line up the edges to make sure it is one or the other.
Have you ever heard of the "three-color rule"?

http://www.cubestation.co.uk/cs2/index.php?page=3x3x3/cfop/cross/cross

Scroll about 2/3 of the way down.
 
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#23
Do you do lots of 3x3? If you have four edges wrong and it's not a Z or H perm, then it's an O or W perm (W perm has some opposite edges)
This is not exactly true. When I have an O-perm, they are in correct relation to each other. This means, I will have to add corners into my recognition. Detecting "3x3 PLLs" isn't the best method, I guess.

I also tried to detect patterns like Dan does but I have a weird system which doesnt work well, at least for me.

Any other ideas?
 

blade740

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Thread starter #24
Do you do lots of 3x3? If you have four edges wrong and it's not a Z or H perm, then it's an O or W perm (W perm has some opposite edges)
This is not exactly true. When I have an O-perm, they are in correct relation to each other. This means, I will have to add corners into my recognition. Detecting "3x3 PLLs" isn't the best method, I guess.
If the corners are solved and the edges are correct in relation to each other, there are only 3 possibilities: solved, H perm, and O perm. You should be able to tell those three apart.
 
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#25
(Sorry for my English :p)

By Reason of the terrible ([-]x, -x) move (for me), I used the method in this thread.
I found 2 more algs (Inverted), which don't use this move, except of the last move.

NA: / (3, 3) / (1, 0) / (-2, 0) / (4, 0) / (-4, 0) / (-2, 0) / (-1, 0) / (-3, -3) (matching bar at DL)
OA: / (3, 3) / (1, 0) / (-2, 0) / (4, 0) / (-4, 0) / (-2, 0) / (5, 0) / (-3, -3) (matching bar at DR)
 
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#27
For NN I use the Adj-Alg (I do a normal Vandenbergh Solution at CP-Skip). I'm able to execute that algorithm in 4 Seconds.
For OO I currently use the "normal" Alg and then the Adj-Alg.
 
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#28
I'm so sorry. This hasn't been replied to for 6 1/2 years, but I need to know:

Is this for corner or edge? Because the edges don't seem to move, only the corners
 
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#29
I'm so sorry. This hasn't been replied to for 6 1/2 years, but I need to know:

Is this for corner or edge? Because the edges don't seem to move, only the corners
This solves parity during corner permutation instead of during edge permutation. The main pro to it is that it has less algs to learn, but now that cubeshape parity is a thing, this should probably be disregarded if you want to get world class.
 
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