Imo for Fridrich users you'll get most utility by just learning the latter step (LE + CO) - it's easy to simply leave a slot that has a corner already done in the middle of your solve, and then make sure by your final pair you've solved EO intuitively too.
That was all I was proposing. I thought it to be a trick for ZZ or Petrus users mainly, and knowing a few cases may come in handy if the first step is skipped entirely in a CFOP solve.
Don't be misguided by the hunt for perpetual motion. Think broader and remember the balance that comes with restriction. Search instead for the imbalance.
Hi all,
Before I start, I've developed this alot more than most that post in the new subset thread, that's why I've decided on a new thread. Just a clarification.
This is something I've been working on for a few weeks now and I'm finally able to announce it! It's a bit like MGLS & L2L4.
Essentially, on your last slot you solve EO + F2L corner then you solve F2L edge + CO. 65 cases for the first step and 34 for the second step.
I've only published about half of the first steps algs, due to a few reasons. It can be done intuitively, the cube images are kind of confusing, and I'm back in school now. No time.
I've settled on the name JJLS, for now. I need to give a huge thank you to qqwref for generating the algorithms for me and helping me along the way. You're the best!
Anyway, here's an example solve and the link to the website.
U2 B F2 R L' D' R2 D2 L' R' D' U R B2 R' F2 L' F' U2 R' L2 F L2 F' B'
y x2
R D R' D2 U' F2
U2 L' U L U R' U R
L' U' L U' L' U L
y U2 R U2 R2 U' R2 U' R'
L' U' L y' R U R'
R U R' U2 R U2 R' U2 R U' R'
y' R U' R U R U R U' R' U' R2
After solving EO and inserting the last slot corner,instead of solving the edge and orienting last layer corners,what if we permute the corners and we can do 2-gll for the rest.Because the case count for the CO is 34 and for permutation it is less than 5 or 6 only.Also if we use this type of approach for zz or petrus it will be easy because they don't have to learn the first step because the edges are pre oriented.Also if you do first step you could get a PLL which may be v-perm,y-perm,e-perm & n-perm which are quite bad cases to execute which can be eliminated by the permutation of corners.