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How Many Algorithms Do You Have Memorized ?

How Many Algorithms Do You Have Memorized for 3x3 ?

  • 1-50

    Votes: 22 26.2%
  • 51-100

    Votes: 20 23.8%
  • 101-150

    Votes: 16 19.0%
  • 151-200

    Votes: 6 7.1%
  • 201+

    Votes: 20 23.8%

  • Total voters
    84

PapaSmurf

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Joined
Jan 4, 2018
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1,103
WCA
2016TUDO02
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253 ZBLL algs, about 5 WVs, 24 COLLs which I don't know the ZBLLs for, 5 WVCPs, maybe 10 TTLLs and TSLEs, both O perm+DF-FR swap (don't ask), about 10 ELLs, UFR-LBD+UF-UR, 25 OLLs (not counting OCLLs), a lot of alt PLLs including OH (probably 20+ in total, a lot of them U perms) and quite possibly a few others. If we include non 3x3, I know CLL and EG-1 for 2x2 plus other algs for other events. So, I know at least 355 algs for just 3x3.
 

One Wheel

Member
Joined
Feb 24, 2016
Messages
2,883
Location
Wisconsin
WCA
2016BAIR04
24 OLL algs, if you count mirrors
21 PLL algs, including mirrors, plus alternate algs for U and H.
Arguable whether I know any algs for f2l or it’s just intuitive at this point, some intuitive solutions are in muscle memory.

Non-3x3:
Odd OLL parity
Even OLL parity
Opposite and adjacent PLL parity
Roughly half a dozen CO algs for Megaminx
Sledge and double sledge for Skewb
Edge flip for pyraminx
Single edge orientation, adjacent corner swap, U-perm, and opposite parity for Square-1
6 algs for M2 3BLD (M-slice and parity)
4 more algs for r2/m2 4BLD
3 more algs for 5BLD U2 +centers
6 algs for Ortega that aren’t shared with 3x3

So 47 specifically 3x3 algs, give or take. About 83 total algs. Just enough to solve all WCA puzzles. I would like to finish learning OLL, just because it would help my 4x4 times. I may also need to learn a few more Square-1 algs to make a cutoff, and eventually some big-blind center comms.
 

Nilsibert

Member
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May 25, 2013
Messages
422
Location
Switzerland
WCA
2014FREY01
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Full PLL =21
Alternative PLL algs roughly =12
Full OLL =57
Alternative OLL Algs roughly =5
COLL -S/AS 28-5 OCLLs incl. in OLL =23
Alternative COLL algs about 3
2GLL T set 12-1 incl. in COLL =11
2GLL U set (currently learning) =4

If I did the math right, that would amount to 136 :)
 

Zain_A24

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Aug 14, 2019
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253 ZBLL algs, about 5 WVs, 24 COLLs which I don't know the ZBLLs for, 5 WVCPs, maybe 10 TTLLs and TSLEs, both O perm+DF-FR swap (don't ask), about 10 ELLs, UFR-LBD+UF-UR, 25 OLLs (not counting OCLLs), a lot of alt PLLs including OH (probably 20+ in total, a lot of them U perms) and quite possibly a few others. If we include non 3x3, I know CLL and EG-1 for 2x2 plus other algs for other events. So, I know at least 355 algs for just 3x3.

Wow. It's like another language to me. :D
 

efattah

Member
Joined
Feb 14, 2016
Messages
711
LMCF: about 310 algorithms, including full EG, Waterman sets 1-7, E2L pair sets, E2L triplets sets, UD transition sets, full L5E, L6E special cases
 

Solvador Cubi

Member
Joined
May 4, 2016
Messages
178
Location
USA
Since it's been a few days since opening the poll, (as of 9/3 there has been 65+ votes.)
I guess it's time for some extrapolation speculation. :)

It is interesting that the results so far are showing some fairly equal distributions across 4 of the segments.
It's not difficult to see how different level of cubers (beginners to experts) fit into them.

I guess once someone knows 150+ algs, they are serious and generally keep going to 200+.
I personally didn't think there would be so many 200+ !!! perhaps I should have made options of higher counts.

anyway, thanks everyone, I was just curious.


-= Solvador Cubi
 

efattah

Member
Joined
Feb 14, 2016
Messages
711
Things have changed in cubing and will keep changing; even around 2014 probably very few people knew 200+ algorithms. In those days CFOPers most just had OLL/PLL. Then some people started learning OLLCP and VLS and gained an advantage, so then some learned ZBLL, then Jabari learned 1LLL (or most of it, 2000+ algs), and so to stay competitive the required algorithm count keeps increasing and will probably keep increasing for a while.
 

TheKravCuber

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Joined
Apr 4, 2019
Messages
62
Location
South Africa
WCA
2019MARA05
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For actual speed solving, 24 :confused: :?.... Still have to learn the sune, anti-sune, and pi CMLL algs....
Although I do also know T-Perm, the three special M2 cases(because cycles don't count:p) and M2 parity. So that brings total alg count to 29 algs
 

GAN 356 X

Member
Joined
Aug 10, 2019
Messages
1,396
Location
Somewhere in the cubing universe
For actual speed solving, 24 :confused: :?.... Still have to learn the sune, anti-sune, and pi CMLL algs....
Although I do also know T-Perm, the three special M2 cases(because cycles don't count:p) and M2 parity. So that brings total alg count to 29 algs
I highly recommend learning y perm, j perm next as it is often used in other algs like n perm. y perm permutes the corners and makes you end up with an edge cycle. it also contains two of the olls
 

Zain_A24

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Aug 14, 2019
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Lol. What the hell is an o perm? DF-FR swap? And here I am, after just learning all the plls (yes, I just learnt n perm at long last) and am facing the massive task ahead: learning full oll

I currently only know part of PLL part of OLL, and PBL for ortega.
Good Luck with full OLL.
 
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