Beginner Blindsolving OP/M2 Questions

Loic Gagnon

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Joined
Mar 15, 2017
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Hi, i'm a relatively new blindsolver and have just started practicing solves.
During my practice, i encountered a huge problem:
At the end of my M2 targets there were always two unsolved edges, The Buffer (DF or U using Speffz) and the target position (UB or A using Speffz). I do the Q algorithm and it brings me to the A setup move, the i do the A setup move and it brings me back to A over and over again in a loop.

Any advice? Thanks!
 
Hi, i'm a relatively new blindsolver and have just started practicing solves.
During my practice, i encountered a huge problem:
At the end of my M2 targets there were always two unsolved edges, The Buffer (DF or U using Speffz) and the target position (UB or A using Speffz). I do the Q algorithm and it brings me to the A setup move, the i do the A setup move and it brings me back to A over and over again in a loop.

Any advice? Thanks!
Hmmm. I'm not the best at blind but did you have an odd number of letters in corners? That might be the problem?
 
Yes,it's just parity. In 50% of your solves you will have an odd number of edge targets and an odd number of corner targets (it's never one or the other, always both).
As you have noticed this leaves you off by M2 after edges and you'll have a similar complication with corners. To counteract this you need to do the parity alg after edges and before corners. This is D' L2 D M2 D' L2 D. Try it on a solved cube to see what it does.
If you are memorising using letter pairs it's always obvious when you have an odd number.
 
Yes,it's just parity. In 50% of your solves you will have an odd number of edge targets and an odd number of corner targets (it's never one or the other, always both).
As you have noticed this leaves you off by M2 after edges and you'll have a similar complication with corners. To counteract this you need to do the parity alg after edges and before corners. This is D' L2 D M2 D' L2 D. Try it on a solved cube to see what it does.
If you are memorising using letter pairs it's always obvious when you have an odd number.

So you're saying every solve i should leave the D(UL) till the end so i can do this algorithm? Because when i do it, there is only the target position and buffer remaining i can't finish it.
 
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