Arendil
Regular
This probably isnt original (Though I did check the Wiki) but anywayyy, I was just kinda messing with the cube the other day and figured out a new algorithm for the Ja perm:
(R' U L' 2U R U' L) U' (R' U L' 2U R U' L)
I thought it was cool because its only one move different from the Nb perm: (R' U L' 2U R U' L) (R' U L' 2U R U' L)
(R' U L' 2U R U' L) U' (R' U L' 2U R U' L)
I thought it was cool because its only one move different from the Nb perm: (R' U L' 2U R U' L) (R' U L' 2U R U' L)