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Recently, I noticed that it's possible to execute the two possible moves for a given position (rotating an up corner and a down corner) at the same time - even in different directions. This is because no pieces are shared by the two moves. Now, if you recall, the standard Pochmann method doesn't involve any pin movements right after the flip - the moves right before and right after the flip are the same as two possible moves for that position. So you can execute them both at the same time with careful finger placement.
I can see two possible ways to take advantage of this. The first way is to execute both moves before the flip; this would require memorizing the first move on the back side, which you probably already do. You would then flip the puzzle while changing pins, and start off with the second move. The second way is to memorize the alignment of the first side's cross, flip, and then do both moves at once. This would give you lookahead to the next move on the second face, but might be slower to execute.
If there are any fast (sub-10, say) clock solvers reading this, what do you think? Is this already well-known? Is it doable at speed? And could it save any time?
And here's the bonus trick: Say you solved the puzzle to a position rotated by some multiple of 90 degrees by accident. You can rotate all 18 clocks at once by moving the pins into a diagonal arrangement (Ud dU, or dU Ud) and then rotating both top clocks by the same amount.
I can see two possible ways to take advantage of this. The first way is to execute both moves before the flip; this would require memorizing the first move on the back side, which you probably already do. You would then flip the puzzle while changing pins, and start off with the second move. The second way is to memorize the alignment of the first side's cross, flip, and then do both moves at once. This would give you lookahead to the next move on the second face, but might be slower to execute.
If there are any fast (sub-10, say) clock solvers reading this, what do you think? Is this already well-known? Is it doable at speed? And could it save any time?
And here's the bonus trick: Say you solved the puzzle to a position rotated by some multiple of 90 degrees by accident. You can rotate all 18 clocks at once by moving the pins into a diagonal arrangement (Ud dU, or dU Ud) and then rotating both top clocks by the same amount.