miniGOINGS
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- Joined
- Feb 27, 2009
- Messages
- 3,049
and i do this algorithm when i have all sides (of the last layer) with one wrong edge except for one side, which is complete?
The back face is solved. I like this one as opposed to M2 U(') M' U2 M U(') M2 because if you see a solved side, you put it to the back and then you can recognize which cycle it is.