D2 B D R2 D2 U F2 U2 L2 R2 B2 L2 U' F' U F L' R' F L'
z
L2 U2 B2 D' L' F // CPFB
R U' M2 U r' U' r' // SB/F2L
R2 U' S' U2 S U' R2 // PLL
Another short one! This time I ended up with an Ua PLL. I tried to solve them earlier (handling the rest as a skeleton), but couldn't find anything where I could utilize a cancellation. Ah, anyway.
Next: D R2 U2 L F2 R F2 L U2 R2 B2 U2 L D F D U' F' L R' B2
D2 B D R2 D2 U F2 U2 L2 R2 B2 L2 U' F' U F L' R' F L'
z
L2 U2 B2 D' L' F // CPFB
R U' M2 U r' U' r' // SB/F2L
R2 U' S' U2 S U' R2 // PLL
Another short one! This time I ended up with an Ua PLL. I tried to solve them earlier (handling the rest as a skeleton), but couldn't find anything where I could utilize a cancellation. Ah, anyway.
Next: D R2 U2 L F2 R F2 L U2 R2 B2 U2 L D F D U' F' L R' B2
L D2 F B2 L B U F R' F B D2 F' R2 B' D2 B D2 L2 F' D2
y z'
R' u2 R' U' R B // CPFB
r R U (F2 M' F2 M) R2 U r' // SB
U M' // LSE
Here I actually used a little FMC! The (F2 M' F2 M) part would not be necessary for the SB; my first SB was without it. But then I noticed that if I do a U M' for the LSE, I end up with only 3 edges at the wrong place (white-orange, red-green, red-blue). It's called a skeleton. So I looked through the solution where can I insert a simple 3-perm. Lo and behold! 18-STM solution.
Next: U L' B D' F B U F U' B2 D' B2 R2 U2 L2 D F2 U' B2 R
L D2 F B2 L B U F R' F B D2 F' R2 B' D2 B D2 L2 F' D2
y z'
R' u2 R' U' R B // CPFB
r R U (F2 M' F2 M) R2 U r' // SB
U M' // LSE
Here I actually used a little FMC! The (F2 M' F2 M) part would not be necessary for the SB; my first SB was without it. But then I noticed that if I do a U M' for the LSE, I end up with only 3 edges at the wrong place (white-orange, red-green, red-blue). It's called a skeleton. So I looked through the solution where can I insert a simple 3-perm. Lo and behold! 18-STM solution.
Next: U L' B D' F B U F U' B2 D' B2 R2 U2 L2 D F2 U' B2 R