LBL for big cubes?

[WaffleCuber]

Everybody tried this when they first got a 4x4/ first big cube, I was wondering if this is possible with no prior steps. I'm sure it wouldn't be reasonable for speed solving. Has anyone made a method for this?

 

[asacuber]

Well I used 5x5 knowledge and intiutiveness to solve a 4x4 LBL once.

I'm not sure what K4 is about tho( I think its kinda similar to LBL, have to clarify)

 

[applezfall]

Well I used 5x5 knowledge and intiutiveness to solve a 4x4 LBL once.

I'm not sure what K4 is about tho( I think its kinda similar to LBL, have to clarify)

in k4 you solve the centers than solve it lbl

 

[shadowslice e]

Have a look at k4, k5 or OBLBL

 

[DGCubes]

It's possible.

 

[Nicky Steingraber]

People have done it like this guy for example

 

[cuber314159]

It's possible, I did it on 4x4x4 once solving one layer, then centres them edges then finishing it off but I reckon 4OH is faster unless you do a lot of practice

 

[I_<3_SCS]

It's possible, I did it on 4x4x4 once solving one layer, then centres them edges then finishing it off but I reckon 4OH is faster unless you do a lot of practice

4OH = 4x4 one handed?

 

[LegendaryMJS]

I have figured the whole thing until the OLL. I am stuck there but I think it's definitely possible. Once I finished F2L only the yellow edges were not paired. Stuck there for now. Any ideas?

 

[shadowslice e]

I have figured the whole thing until the OLL. I am stuck there but I think it's definitely possible. Once I finished F2L only the yellow edges were not paired. Stuck there for now. Any ideas?

Have a look at k4 LL, commutators and conjugates.

 

[TipsterTrickster]

I just finished a LBL 7x7 solve and it took forever so it is definitely way better to do reduction

 

[TipsterTrickster]

I have figured the whole thing until the OLL. I am stuck there but I think it's definitely possible. Once I finished F2L only the yellow edges were not paired. Stuck there for now. Any ideas?

Use l' U2 l' U2 F2 l' F2 r U2 r' U2 l2