3x3x3 F3L - is it possible?

Is 3x3x3 F3L possible?

  • yes, possible to learn

    Votes: 5 13.2%
  • no point too hard

    Votes: 13 34.2%
  • dont know

    Votes: 6 15.8%
  • dont care

    Votes: 14 36.8%

  • Total voters
    38

dannah

Regular
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Messages
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Location
surrey,UK
F3L is an idea where you get the F2L and the bottom corners in together, then use algorithims from the roux method,
to get the last layer done or just the cross as you have already permuted all the corners?
would it need thousands of algorithims?
 
F3L is an idea where you get the F2L and the bottom corners in together, then use algorithims from the roux method,
to get the last layer done or just the cross as you have already permuted all the corners?
would it need thousands of algorithims?

F2L + the bottom corners = LL everything but edges? (if you do F2L on top beginner style, otherwise this makes no sense
CMLL won't help you solve the edges

Another thing you might be saying is to solve the F2L pairs without solving the cross, then doing CMLL and edges (which would be pretty much roux)

either way, No.
 
F3L is an idea where you get the F2L and the bottom corners in together, then use algorithims from the roux method,
to get the last layer done or just the cross as you have already permuted all the corners?
would it need thousands of algorithims?

Of course F3L is possible, juste solve the whole cube using any method :p

Seriously, it's a poor name choice, let's just say columns. Basically what you're asking for is CFCE with step 2 and 3 merged. It is always possible, but not very practical because after having solved at least one column you lose the freedom of the U layer.
 
It is not possible because that is the equivalent of a LL skip every solve which normally it happens every 10,000 solves.

Nope, because remember the LL edges will still be unsolved.

I think it's definitely possible, no doubt, but I'm not sure it'll be efficient since corners are easy to do on the LL anyway. Also, I can't imagine that it's very fast. Interesting idea though, and would like to be proved wrong.
 
I'm sure it is possible. There are 4.3E19 positions for a 3x3, and I'm sure there are alogrithms out there in that number that can do it.
 
I've just been messing around on my cube, and it really isn't hard at all. It's basically like doing F2L twice as much. First a pair up the edge with the yellow corner. Then I pair up the white corner with the pair already formed, and insert. The only thing is, I can imagine it would be difficult to preserve the Yellow corners in the correct place& orientation, while doing the others.

Update: I did 2 F3L 'pairs' and it was ok. Managed to preserve the first one while doing the second. The third is hard.
 
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Ohh I think you might be decribing PCMS. Should it look like this?
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or this? (which is basically CFCE)
attachment.php
 

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Well, 'F2L' is describing the step that fully solves the first two layers, so F3L would be solving the whole cube. maybe call it F2L+?

but isn't that winter variation?

EDIT:Sorry, winter variation is just orientation, but it shouldn't be too hard to get algs that solve CLL while doing the last pair.
 
oh ok thank you

the 2nd one

no you have not skipped the last layer you have skipped the last 4 corners
 
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oh ok thank you

the 2nd one

no you have not skipped the last layer you have skipped the last 4 corners
Ah okay. So what you're describing is CFCE, or a variation of CFOP which is Cross, F2L, Corners, Edges. Basically what you do is you solve the F2L normally, and you do one of 42 algs to orient and permute the corners. Then you do one of (idk how many) algs to solve the remaining edges. It's pretty hard to solve last layer corners while solving F2L, that's why theres an alg set to just do it in one step afterwards.
 
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