Transition from ZZ-VH to ZZ-b
- Thread starter andreassb
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I know there are certain cases that simply vanish with ZZ-b. Among these is the Sune case. (Not the whole sune class of cases, but the particular standard sune.)
Since you are solving 2 edges across from each other, the result is that either all 4 are correct by the time you get to the last layer, or the two unsolved ones are swapped. Since Sune includes an edge cycle, it's out. I don't know what other COLL cases/algorithms do this, though, but it's something to think about.
Anything that has as a side effect a 3-cycle of edges cannot be a ZZLL case.
Edit: Clarified things. The first version of this post was wrong.
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I was thinking kind of the same things. But i am not sure that is how it works. Take these cases, for example:
U' B U' F U2 B2 D' R2 U D F' U' B
B L U L' U' B' L' U' B' U B L U2
F U F' U F' U' F2 U' F2 U2 F
L2 D' R B2 R' D L2 U L' U L U'
L U L' U L2 D R' F2 R D' L2 U'
EDIT: Ah okay, you edited your post ;-) It makes more sense now.
U' B U' F U2 B2 D' R2 U D F' U' B
B L U L' U' B' L' U' B' U B L U2
F U F' U F' U' F2 U' F2 U2 F
L2 D' R B2 R' D L2 U L' U L U'
L U L' U L2 D R' F2 R D' L2 U'
EDIT: Ah okay, you edited your post ;-) It makes more sense now.
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MHordecki
Regular
Basically you could reuse all your 40 algorithms - every COLL case reappears in ZZLL.
Just treat ZZLL as ZBLL that's stripped with factor 1/3 (1 ZZLL case for each 3 ZBLL cases -> 4 ZZLL cases for each COLL case).
Given the fact, you can reuse such algs that are contained in ZZLL. Others are 'just' ZBLL and you will need to relearn them.
To check whether your algorithm is good for ZZLL, execute it and then check edge permutation. If either UF & UB or UR & UL are opposite, it's ZZLL. Otherwise it's ZBLL and therefore not under consideration.
Just treat ZZLL as ZBLL that's stripped with factor 1/3 (1 ZZLL case for each 3 ZBLL cases -> 4 ZZLL cases for each COLL case).
Given the fact, you can reuse such algs that are contained in ZZLL. Others are 'just' ZBLL and you will need to relearn them.
To check whether your algorithm is good for ZZLL, execute it and then check edge permutation. If either UF & UB or UR & UL are opposite, it's ZZLL. Otherwise it's ZBLL and therefore not under consideration.
oll+phase+sync
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1/3 of all LL cases are phased 2/3 are not. If you now pick a random subset of 42 COLL Algorithems, you should a similar ratio.
Obviously one would not pick a random subset, but one with minimal moves - anyway my personal set of algs tell me 1 : 2 is pretty realistic.
I also believe: "if a COLL Case is not solvable by just "touching" 3 Corners, then there is alway a "phasekiller"-Algorithem with less moves "
I cannot proof that, but may be someone has an counter exsample.
Obviously one would not pick a random subset, but one with minimal moves - anyway my personal set of algs tell me 1 : 2 is pretty realistic.
I also believe: "if a COLL Case is not solvable by just "touching" 3 Corners, then there is alway a "phasekiller"-Algorithem with less moves "
I cannot proof that, but may be someone has an counter exsample.
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