The Roux "Example Solve" Game!

U' F2 L2 F2 R2 D' R2 U2 L2 F' U' L' F D' B2 D' F2 R2 B2

I decided to add some commentary this time.

z'
B2 M' B' E U M' U2 B (8) // average
U R' U' R M U' R U' R U' M' r U r' (14) // ahhh no D: y u so long?
R U R' U' R' F R F' (8) // yay unintentional 1 look
U2 M U2 M' U M2 U2 R2 (8) // yay eo skip and super eazy peazy LSEEEzy :D

38 total :)

btw, epic f2b renslay.

Thanks. :)
That E' is an E in your FB.

For your second block, I would use:
r' U r M' U M' r U2 R U' r' (11)
And it's a matching color block with the same CMLL! :-)
 
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Woops I always forget which way E and S go lol. Thanks for the SB solution, I've worked so hard at it lately but it still just screws me over like that. :<
 
Woops I always forget which way E and S go lol. Thanks for the SB solution, I've worked so hard at it lately but it still just screws me over like that. :<

I used to be get confusing with the directions too, but then somebody posted this:
All the slice moves without the apostrophe are going in the direction of normal text reading! :)
So M is from up to down, and S and E from left to right!
 
I used to be get confusing with the directions too, but then somebody posted this:
All the slice moves without the apostrophe are going in the direction of normal text reading! :)
So M is from up to down, and S and E from left to right!

:O amazying, i had no idea.
 
My first try (speedsolve solution):

U' F2 L2 F2 R2 D' R2 U2 L2 F' U' L' F D' B2 D' F2 R2 B2

x2 y'
U B2 D2 Rw U2 Rw' F B2 U Rw B' // FB(11), bad FB
U2 R' U R U' R' U2 R' U M U2 M' U' R // SB(14)
U2 F R U R' U' F' // CMLL(7), lucky cmll
U M' U M' U' M' U' M' U M U2 M2 U' M2 U2 // LSE(15), Ok for a speedsolve

47 STM


First FMC solution

y x
F2 R F2 U R U' B // FB(7)
U M' R' U M2 Rw U' R // SB(8)
U R2 U' R F2 R' U R F2 R // CMLL(10)
U M' U' M U' M' U2 M2 U // LSE(9)

34 STM (40 HTM :()
 
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My first try (speedsolve solution):

U' F2 L2 F2 R2 D' R2 U2 L2 F' U' L' F D' B2 D' F2 R2 B2

x2 y'
U B2 D2 Rw U2 Rw' F B2 U Rw B' // FB(11), bad FB
U2 R' U R U' R' U2 R' U M U2 M' U' R // SB(14)
U2 F R U R' U' F' // CMLL(7), lucky cmll
U M' U M' U' M' U' M' U M U2 M2 U' M2 U2 // LSE(15), Ok for a speedsolve

47 STM

First block with the same colors:
y' x'
R F2 R2 E2 L F' R' r' F (9)
or:
y' x2
R D2 U R2 S2 M r' F (8)
Can't see any better; and S2 M seems uncomfortable.

LSE:
U M' U M' U2 M U M' U2 M2 U' M U2 (13)

But it is a pretty good solution for a speedsolve.
 
First block with the same colors:
y' x'
R F2 R2 E2 L F' R' r' F (9)
or:
y' x2
R D2 U R2 S2 M r' F (8)
Can't see any better; and S2 M seems uncomfortable.

LSE:
U M' U M' U2 M U M' U2 M2 U' M U2 (13)

But it is a pretty good solution for a speedsolve.

I couldn't see any better solution in the inspection time with my speedsolve colors.
In the first block in never do S or E turns even if i see it, i don't know why but the change of the centers confuses me.


Any suggestions for my FMC solution?
 
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Any suggestions for my FMC solution?

I played with it for 20 minutes, but couldn't any better CMLL/LSE pair (including changing the last R to Rw in the end of the SB).
Both your CMLL and R2 D' R U2 R' D R U2 R does not change the orientation of the edges, so maybe you can try to orient the edges during the SB.
 
U' F2 L2 F2 R2 D' R2 U2 L2 F' U' L' F D' B2 D' F2 R2 B2

Another solution, but the LSE is sooo long

x' y
R' U2 F U' R U B' Rw B' // FB(9)
U2 R U S' U' S R U M' U' Rw' // SB(11-2)
Rw U R' U Rw U2 R' // CMLL(7-2)
U M' U' M U' M' U M U2 M' U' M2 U2 // LSE(13)

36 STM
 
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U' F2 L2 F2 R2 D' R2 U2 L2 F' U' L' F D' B2 D' F2 R2 B2

y R2 F U' r z' U' R r B'
U' M' U R U R2 U' R2 M U M' U' R
U F U' L' U R2 U' L U R' Lw' U' x'
M U M' U2 M2 U' M2 U2 M U2


gross

Solution

Your LSE seems too pro. Can you make a text or video tutorial on how you do it?
 
Scramble:
U' F2 L2 F2 R2 D' R2 U2 L2 F' U' L' F D' B2 D' F2 R2 B2
y2 x' L2 D2 x U r' D2 U R D [8/8]
U R U M2 U R M U M' U' r [11/19]
R U2 R' U' R U' R2 U2 R U R' U R [13/32]
M2 U' M2 U2 M' U2 M [7/39]

Really interesting solve for me. What do you guys think?
 
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U' F2 L2 F2 R2 D' R2 U2 L2 F' U' L' F D' B2 D' F2 R2 B2

x2 y
D L U' L' D U L U L' U' L' U' L U2 L' U' L // FB // 17/17 Woah lol
U2 R' U R U' R U R' U B U' B' U' R' U' R // SB // 16/33 Noob building blocks here!
R U' L' U R' U' L // Orient corners // 7/40
L’ U2 L2 U L2’ U L2 U2 L’ // Permute corners // 9/49
M U' M2 U' M U M' U2 M // F2L? lol // 9/58
M' U M U M' U2 M U' M' U' M U' // ELL // 12/70

This solve was possible thanks to Deedubb's beginner Roux tutorial. Thanks Deedubb. I can do Roux-ish style solves now.
 
U' F2 L2 F2 R2 D' R2 U2 L2 F' U' L' F D' B2 D' F2 R2 B2

x2 y
D L U' L' D U L U L' U' L' U' L U2 L' U' L // FB // 17/17 Woah lol
U2 R' U R U' R U R' U B U' B' U' R' U' R // SB // 16/33 Noob building blocks here!
R U' L' U R' U' L // Orient corners // 7/40
L’ U2 L2 U L2’ U L2 U2 L’ // Permute corners // 9/49
M U' M2 U' M U M' U2 M // F2L? lol // 9/58
M' U M U M' U2 M U' M' U' M U' // ELL // 12/70

This solve was possible thanks to Deedubb's beginner Roux tutorial. Thanks Deedubb. I can do Roux-ish style solves now.

I knew my method wouldn't be the most efficient, but that's awesome that you were able to do it :)
 
Your LSE seems too pro. Can you make a text or video tutorial on how you do it?

He just used misoriented centers.

Maybe you can see what did he do on this one:

On a solved cube do an M move then the inverse of his solution:
M (M U M' U2 M2 U' M2 U2 M U2)'
=
M U2 M' U2 M2 U M2 U2 M U' M'
Solution for this scramble (this is what he actually did):
M U M' // EO
U2 M2 U' // UL-UR
M2 U2 M U2 // M-perm
M' // we added an M in the beginning, so we have to undo it.

It is quite simple, isn't it? Becuse of the additional M/M' move, the centers became oriented, and you can see what's going on.
Using misoriented centers it is still the same, but a little harder to see.

Now try it on the original cube:
Scramble:
(M U M' U2 M2 U' M2 U2 M U2)'
=
U2 M' U2 M2 U M2 U2 M U' M'
Solution:
M U M' // EO with misoriented centers (the centers are non-matching, yet every edge is oriented)
U2 M2 U' // UL-UR (the centers are still non-matching)
M2 U2 M U2 // M-perm. You can see it as M (matching the centers) + M U2 M U2
 
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He just used misoriented centers.

Maybe you can see what did he do on this one:

On a solved cube do an M move then the inverse of his solution:
M (M U M' U2 M2 U' M2 U2 M U2)'
=
M U2 M' U2 M2 U M2 U2 M U' M'
Solution for this scramble (this is what he actually did):
M U M' // EO
U2 M2 U' // UL-UR
M2 U2 M U2 // M-perm
M' // we added an M in the beginning, so we have to undo it.

It is quite simple, isn't it? Becuse of the additional M/M' move, the centers became oriented, and you can see what's going on.
Using misoriented centers it is still the same, but a little harder to see.

Now try it on the original cube:
Scramble:
(M U M' U2 M2 U' M2 U2 M U2)'
=
U2 M' U2 M2 U M2 U2 M U' M'
Solution:
M U M' // EO with misoriented centers (the centers are non-matching, yet every edge is oriented)
U2 M2 U' // UL-UR (the centers are still non-matching)
M2 U2 M U2 // M-perm. You can see it as M (matching the centers) + M U2 M U2

Thanks for explaining. Quite interesting. I'm gonna try to incorporate them in my solves. But, I usually do R or Rw at the end of the SB so that my centers are oriented after I finish my CMLL.
 
Scramble:
U' F2 L2 F2 R2 D' R2 U2 L2 F' U' L' F D' B2 D' F2 R2 B2
y2 x' L2 D2 x U r' D2 U R D' [8/8]
U R U M2 U R M U M' U' r [11/19]
R U2 R' U' R U' R2 U2 R U R' U R [13/32]
M2 U' M2 U2 M' U2 M [7/39]

Really interesting solve for me. What do you guys think?

Something is wrong there.

Thanks for explaining. Quite interesting. I'm gonna try to incorporate them in my solves. But, I usually do R or Rw at the end of the SB so that my centers are oriented after I finish my CMLL.

Me too, so I never use misoriented centers in my speedsolves. Although they can be helpful, as you can see, so maybe they worth to learn.
 
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