# The Roux "Example Solve" Game!

#### narusite

##### Member
NEXT : U2 L2 R U2 B2 F2 R B2 F2 R2 U2 B L2 U2 L' U' B' L2 B2 F' D2
Code:
yx'//inspection
B Rw2 F' U' M' U R B' // FB - 8
M' U2 Rw' U R U Rw M2 U' Rw' //SB - 10/18
U2 RUR'U' R'FRF' //CMLL1 - 9/27
U R'UL' U2 RU'R' U2 RL //CMLL2 - 11/38
U' M' U' M //arrow - 4/42
U2 M U M //step 4a - 4/46
U M' U2 M //step 4b - 4/50
U' M2 //step 4c 2/52
62h, 73q, 52s, 54e

Next: B2 D U R2 F2 U' B2 F2 D2 F2 U' L' U R2 F2 D2 B' L' F' L2 D'

#### Pyjam

Can't seem to get sub-40 movecount... Can you guys help point out any huge inefficiencies in my solve?

1. Don't be impressed. Sub-40 STM here doesn't mean sub-40 speedsolve, not at all.

2. Optimize your FB and try to solve the DR edge in the same time, or put it in a good place.

3. During SB, play with the wide moves to influence the edge orientation for the next step.

4. Know how your CMLL algs orient the edges, and try different algs (OLLCP) to either solve the orientation, or get 4 bad edges, or get a better permutation. It's a good occasion to discover and learn some interesting and easy OLLCP alg.

5. During LSE, don't necessarily try to solve UR and UL first. UF and UB are good too, even DF and DB (like in the example above).

Hope this help and you'll get better result in the game.

#### Pyjam

Can't seem to get sub-40 movecount... Can you guys help point out any huge inefficiencies in my solve?
Here's what I can do with your last solve.
During SB, I've changed R' by r', and not only the SB is shorter but in result there are 2 bad edges instead of 6.
Then I put the bad edges in the best position with M2' which is cancelled with the first move of CMLL (R2').

z2 y' U F' U F' U R B' // fb
U' R U2 R U' r' U r' U R // SB, only 2 bad edges
U2 r2' // put the bad edges in good position
F U' F U F2 R2 U' R' F R // CMLL + EO (1 move cancelled with the previous step)
M U2 M' U M2' U2' M U2 M' // LSE

#### ImmolatedMarmoset

##### Member
D U2 R’ F R r B’ //First Block (7/7)
U2 R M U2 M2 r’ U’ r U’ M R U’ R’ //Second Block & CMLL skip (13/20)
M’ U’ M U’ M’ U’ M2 U’ M’ U2 M U2 //LSE (12/32)
Nice CMLL skip. Would have looked for better but you can’t beat a CMLL skip.

EDIT: next scramble: F2 R' F2 L2 B2 F2 L B2 D2 U2 L F' R' D' L2 U R D' B' F' D2

Last edited:

#### narusite

##### Member
Next scramble: F2 R' F2 L2 B2 F2 L B2 D2 U2 L F' R' D' L2 U R D' B' F' D2
Code:
y x//inspection
U' R2 B2 F' D' //FB - 5
R' U' M2 U R2 M2 R' U' M' U' R //SB 11-16
U2 F RUR'U' F' //CMLL1 7-23
U R'UL' U2 RU'R' U2 RL //CMLL2 11-34
M' U M' U //arrow 4-38
M U M //step 4a 3-41
U M' U2 M' U' M2 U //4b 7-48
M2 U2 M U2 M' //4c 5-53
66h, 83q, 53s, 55e

Pretty happy with my F2B, but if you have advices, (for all my solves), do not hesitate.

Next: L2 B2 F2 U R2 B2 D2 U L2 F2 U2 B' D' B2 U' B' R' D' U' B

#### WolfX

##### Member
Hey. I was just seeing your own solution and I come with the following simple question: Why did you start the second block with the M move since you can build the second block exact the same way without doing an extra move? Also I liked what you did with the first block.

#### Pyjam

Its not something one can do in a speedsolve. It's an optimization. I added it to get a better LSE case. Remove it and it's not that nice.

#### WolfX

##### Member
U R F2 D B U R B2 F2 L' R2 U R' L D L2 F U2 B U2

I was trying to set up my first block in inspection but I was struggling to find a fast way to build the FB. Usually the FB takes about 7 or 8 moves. I would like someone to demonstrate their own solution not only for the first block but all the other steps along.

#### narusite

##### Member
U R F2 D B U R B2 F2 L' R2 U R' L D L2 F U2 B U2
I'm clearly not an expert, and I still do unlimited inspection, so…
First, I rotate the cube (with y), to see if I see pairs. So first, I see green-orange attached to green center, then 3 red attached to red center, and blue-white attached to blue.
For green-orange, the orange-yellow edge is attached to the green-orange, and even if D2 S2 quickly makes a pair, since it's attached to green-orange, I pass.
Matching the green-white with green-white-orange seems tedious, too, so I go to red.
Since it's a little bit overcrowded, I check the blue-white first, but the pieces for the pair (blue-red/blue-red-white and blue-orange/blue-orange-white) are adjacents, so I come back to red.

Again, red-blue and red-blue-white are next to each other, same with red-white and red-green-white, so I check with red-yellow.

With red-yellow, I see that R F' R2 F can make/insert the red-blue pair easily, and U' M U M2 B for the red-green pair.
Playing a little bit more I came up with:
x2y2 //
R F' R2 F B u' F' u R' U' M F //FB 8
M R U R2 U2 R' M' U' Rw //SB 9-17

Since orange-blue was already in place, I use that as a "dr edge", and make the pair with M, and insert with RUR2.