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The Mehta example solve game

carcass

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U' R B2 R2 F2 U2 R2 D2 F' U2 R2 F2 R2 U' L D2 L U' R2 U' F2
z2//Inpsection
L' F' L2 F D' F' u U2 F R' U2 F' U' L' U L F U2 R' U R//Pseudo 2x2x3 cuz that should be the first step of Metha
F2 U F D R' F R2 F' R'//Belt, EO
U R U' R2 U' R2 U' R2 U' R2 U' R' U2 R2//Intuitive TDR
U R' U' R U2 R D R' U' R D' R2 U R U' R' U R U2//ZBLL
Next Scramble: B2 U L2 D' F2 D B2 R2 U' L2 B U' B2 R D2 L' B F L' R2
 

BenChristman1

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Next Scramble: B2 U L2 D' F2 D B2 R2 U' L2 B U' B2 R D2 L' B F L' R2
This scramble is a joke, right?

45 STM, 43 with cancellations
x2 // Inspection
D2 R' B' L' B2 L R U' R' u2 R F' U' F U' R' // FB+EO Belt (in 16 moves)
R2 U' R2 U R U2 R2 U' R2 U' R2 U2 R // 6CO
R2 U R2 U' R2 U2 R2 // APDR
U' D' M2 U' M U2 M' U' M2 // PLL

Next: B2 L' B2 L2 D2 F2 U2 L D2 U2 R' U R' B D R' F' U' R D' L'
 
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B2 L' B2 L2 D2 F2 U2 L D2 U2 R' U R' B D R' F' U' R D' L
Trick subset-CLS: 54 ETM

S2 U2 S2 U2 L' U L B R F' U F //FB
D' R' u R U2 R' u2 //3QB
R U2 R' U S' U S //EOLE
U2 D' L' R U R' U' L R U2 R' U' R U R' //CLS
U R' U L' U2 R U' R' U2 R L U' D' //PLL

F' L' D2 L' F R2 L B2 D B D' F2 U D L2 D' L2 B2 U B2 D2
 
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Devagio

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R2 L' D F B D' R U' D2 L2 F2 R2 L2 U2 F' D2 B' U
Tried out this cfop-style EO-ledge that I've been experimenting with a lot lately. Its a few moves less efficient than the FB+3QB route, but with all the development in CFOP and its fingertrickability, that move gap should not matter. This however is only worthwhile if at least 3qcross+1pair is planned in inspection and the second pair is tracked, which is a high barrier for intermediate solvers. Also features the anti-APDR path just for the kicks.

y2 x' // Inspection
R' B' // 3q-cross (2/2)
U' R' U' R L' U L // pf2l-1 (7/9)
U R2 U R2 f' L2 f // pf2l-2 (7/16)
U2 R' // last-edge (2/18)
f R S' R F' // EOLE (5/23)
U' R U' R' U2 R U' R' // 6CO (8/31)
R2 U' R2 U R2 U2 R2 // Trangium's Anti-APDR idea (7/38)
U' R U2 R2 U' R' U R' U' R2 U D' R U2 R' // PLL+2c (15/53)

Next: B2 R B R' U2 F' U' R' D2 B2 D2 L B2 U2 R' U2 L' B' L
 
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CuberStache

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Next: B2 R' D2 R' D2 U2 B2 L U2 B2 R D U B' D2 B2 D' L B2 D'
CDRLL/JTLE OS

y2 // Inspection
D2 B' U (B F') // FB (4/4)
u' R2 E' R2 U2 R' u2 // 3QB (7/11)
F' U2 F // EOLE (3/14)
R U' R U' R' U2 R // DCAL (7/21)
D R' U2 R D' R' U2 R' // CDRLL (8/29)
(D' U2) M2 U' M2 U' M U2 M' U' // L5EP (9/38)

6CP/APDR OS

y2 // Inspection
D2 B' U (B F') // FB (4/4)
u' R2 E' R2 U2 R' u2 // 3QB (7/11)
F' U2 F // EOLE (3/14)
U R U' R U' R' U R U' R' U2 R' // 6CO (12/26)
u' R2 U2 S R2 S' // APDR (6/32)
U2 R' U' F' R U R' U' R' F R2 U' R' U' R U R' U R U' // PLL (20/52)

TDR

y2 // Inspection
D2 B' U (B F') // FB (4/4)
u' R2 E' R2 U2 R' u2 // 3QB (7/11)
F' U2 F // EOLE (3/14)
R U R' U R U' R' U R2 U R' U R' // TDR (13/27)
U R' U L U' R2 z' R2 U' L U R2 (U' D') (R' L') // ZBLL (14/41)

NEXT: D' U' L2 R2 U' L2 D' F2 U L2 F2 U2 L D2 L U F' D L D2 R'
 
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CuberStache

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tsmosher

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Next: D L U2 R U' F' R' U D2 F U2 R2 U2 R2 B2 L2 F' R2 B D2 U
This is a method I've been developing based on the beginner's Mehta method.

Namely, I set the DBR corner in place along with its corresponding E edge as an F2L pair.
Then I can perform a shortened set of 6CO/6CP algs (as long as they preserve the DBR corner).
A little L5EOP (with the DR edge) before LSE. (More or less done intuitively.)

This brings me down to knowing:
  • F2L
  • LSE
  • L5EOP (except with S moves)
  • 23 6CO algs
  • 8 6CP algs. (I generally use T-PLL, E-PLL, and Ja-PLL as well to preserve edge phasing.)
Still ironing this method out.
My original intention was to enable the use of OLL/OLLCP-A...

[56 STM]
y' U2 L' U B' D // DL column + DF edge for LSE (5/5)
Uw' U R' Uw2 R' Uw' E R' U R // 3QB (I need to get better at this part) (10/15)
Uw R' U' R // BR pair (i.e., E edge 4) (4/19)
M U2 M' // DB edge (for LSE) (3/22)
U' R D' R U R' D R' // 6CO (8/30)
U' S' U S // EO + DR edge (4/34)
U' R U R' U' R' F R2 U' R' U' R U R' F' // T-PLL, keeping edges phased (15/49)
U2 M' U2 M2 U2 M' U' // LSE (7/56)


NEXT: F2 D F2 U B2 U F2 U L2 B2 F' L' B L U L D' U F2
 
Last edited:

tsmosher

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Aug 30, 2020
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NEXT: D' B F R2 U2 F U2 F U2 R2 F' D L' U' L B2 L B L2
[69 STM / 70 ETM]
x // inspection
F U R U' Rw' D' R2 // 222 (7)
F' L F2 L' F' L F L' // join missing pair (8)
F R U' R' U // insert pair to form 223 (5)
y2 Lw // reposition after block building got a little carried away (2)
Uw R U2 R' // 3QB (4)
D2 U' F U' F' // keyhole join FR pair (5)
D U' L' U L // insert FR pair (5)
Uw' F R U R' U' F' // EO (7)
U' R U2 R' U R U R' D // 6CO (9)
U2 D R2 U' R2 U R2 D' R2 // 6CP + DR edge (DR edge was nothing more than luck) (9)
U' M2 U' M U2 M' U' M2 U // U-PLL (9)


All of my Mehta solves seem to have the problem of high move count. (Low to mid 70s pretty consistently.) Some of that is due to me not wanting to learn more algorithms, I'm sure, but any constructive criticism would be appreciated.

NEXT: B L2 D' B2 U L2 D' B2 R2 D2 L2 U2 R' D2 U2 R U2 F U B2 L
 
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First of all, the right way to solve until EO is:
1x2x3 in DL> 3 belt edges>EOLE.
Next, there is no need to build actual blocks if you're solving a 2x2x3. You can always build pseudo blocks.
You don't have to join pairs during 3QB. You should learn 6CO1 bc It does the same job with fewer moves.
Btw here's my solve:

F U' L2 R U2 R' U' F R' F' R U L' U2 L //2 squares
B' U M' U M //223
U2 R' U R U f' L f2 R U R' U' f'//EOL2E
U' L U' L' U2 L U' L'//TDR
U' F R' F R2 U' R' U' R U R' F' R U R' U' F' U2//PLL


Next: 1. R2 B' L2 F' R2 D2 B2 D2 B U2 R2 B' D' R B2 U R' F2 L' R'
 

tsmosher

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Thank you for your advice!

First of all, the right way to solve until EO is:
1x2x3 in DL> 3 belt edges>EOLE.
I am doing more of a beginner's approach with EO after the belt.
(e.g., In this case, 6-move T OLL is best case EO if you're not doing EOLE.)

See my notes below on why I am building the pair here.

Next, there is no need to build actual blocks if you're solving a 2x2x3. You can always build pseudo blocks.
I think this is one place I need to improve. Any videos you recommend?

You don't have to join pairs during 3QB.
You should learn 6CO1 bc It does the same job with fewer moves.
I'll address both of these at once.

My thought here was that after 6CO2 (in the beginner method), the DRB corner is inserted in order to reduce the number of 6CP algs needed.

If I insert the DBR corner (or DFR corner for that matter) earlier at the same time as my belt,
AND my 6CO algs all preserve this corner (which they do after some slight alg changes),
I was hoping it'd save me the later effort of finding that corner and inserting it awkwardly using R2s/U2s after 6CO2.

6CO1 is generally hard for me to recognize, but I will experiment more with it.
(And try leaving the pair out to see the effect of that as well.)

I think that- ultimately- a lot of it boils down to the fact that better block-building (less moves at the beginning) and more algs (less setup moves for the end steps) are probably the quickest way to shorter solves for me personally.

Thanks again-
Tim.
 
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