The alg learning area

[HowDoIDoCFOP]

On this thread I WILL learn:
Full oll
Full pll
Full EOLE
Full DCAL
Full CDRLL
Full CMLL
Full ZBLL
Full TDR
Full L5EP
Full L6E

Any questions? If not, I'll begin!\
Ill post algs for you if you want to follow along!

 

[NigelTheCuber]

i can share my oll pll algs if you want

 

[HowDoIDoCFOP]

wait ok
nigelthecuber
begin!!

 

[AJT17]

On this thread I WILL learn:
Full oll
Full pll
Full EOLE
Full DCAL
Full CDRLL
Full CMLL
Full ZBLL
Full TDR
Full L5EP
Full L6E

Any questions? If not, I'll begin!\
Ill post algs for you if you want to follow along!

That is a crazy amount of algorithms that you will have to learn, that is over 600 algorithms, for the ones I could find the algorithms for.
INSANE, well good luck on your journey to insanity (or knowledge)

 

[AlphaCuber is awesome]

On this thread I WILL learn:
Full oll
Full pll
Full EOLE
Full DCAL
Full CDRLL
Full CMLL
Full ZBLL
Full TDR
Full L5EP
Full L6E

Any questions? If not, I'll begin!\
Ill post algs for you if you want to follow along!

Why do you wany to learn all these

 

[Deleted member 36445]

Why do you wany to learn all these

y n

 

[IsThatA4x4]

57 + 21 + 56 + 80 + 42 + 42 + 493 + 350 + 16 + 93 i think = 1250 algs WOW!

 

[cuberswoop]

57 + 21 + 56 + 80 + 42 + 42 + 493 + 350 + 16 + 93 i think = 1250 algs WOW!

ZBLL and TDR really sink the boat.

 

[Timona]

ZBLL and TDR really sink the boat.

For real. I actually plan on learning most of the Mehta algsets, maybe just Mehta-OS, definitely not TDR. I don't know if I'll even learn ZBLL

 

[Timona]

Why do you wany to learn all these

Because he can?

 

[Silky]

Clarity on L6E?

 

[Deleted member 36445]

Clarity on L6E?

maybe he is referring to EOLR?

 

[Thom S.]

Clarity on L6E?

L6E is from what I know the fancy, unknown way of saying LSE

 

[Tecknet]

57 + 21 + 56 + 80 + 42 + 42 + 493 + 350 + 16 + 93 i think = 1250 algs WOW!

And I still have trouble with being bothered to switch to complete 2LLL

 

[Timona]

And I still have trouble with being bothered to switch to complete 2LLL

57 + 21

this is all you need then.

 

[IsThatA4x4]

Clarity on L6E?

It's probably L6EP, because full L6E would be
6! x 2^5 x 1/2 = 11250 (not counting for AUF or symmetry)
Edit: with AUFs being accounted for it's probably still closer to 2500

 

[Tao Yu]

good luck ! personally I found full oll quite difficult to learn

btw pll is included in zbll, so it's really not as bad as people in this thread are making it out to be, you only need to learn around 1229 algs actually.

 

[Deleted member 36445]

good luck ! personally I found full oll quite difficult to learn

btw pll is included in zbll, so it's really not as bad as people in this thread are making it out to be, you only need to learn around 1229 algs actually.

the legend.

 

[tsmosher]

good luck ! personally I found full oll quite difficult to learn

btw pll is included in zbll, so it's really not as bad as people in this thread are making it out to be, you only need to learn around 1229 algs actually.

Don't forget EPLL is part of L5EP is part of L6EP.

Not to mention if he ends up using the same COLL for CMLL and CDRLL in some cases.

 

[Silky]

Don't forget EPLL is part of L5EP is part of L6EP.

Not to mention if he ends up using the same COLL for CMLL and CDRLL in some cases.

Okay seems like we'll need to calculate this out now. I want to know exactly how many algs we're talking here. Also does an alg sheet exist for L6EP?