glenjamindle
Member
- Joined
- Oct 17, 2008
- Messages
- 4
Hey all
I'm just downright confused
OLL
PLL
F2L
U Perm
F3L skips
8 LLL = 4 L OLL, 4 L PLL
4 LLL = 2 L OLL, 2 L PLL
3 LLL = 2 L OLL, 1 L PLL
2 LLL = 1 L OLL, 1 L PLL
I mean really now
What is the process, from beginning to end, to solving the cube? Please describe the process and all the possibilities. If you could provide links for all the algs necessary that would be great.
For example>
Step 1
(What are we trying to accomplish before moving to the next step)
Bottom cross
Step 2
(What are we trying to accomplish before moving to the next step)
Bottom corners with respective edges (Fridrich method) (Link)
Step 3
(What are we trying to accomplish before moving to the next step)
Orient Last Layer (OLL)
(Link)
Difference between methods (2 look, 4 look, etc...)
So many (#) of possibilities
Step 4
(What are we trying to accomplish before moving to the next step)
Permutate Last Layer (PLL)
(Link)
Difference between methods (2 look, 4 look, etc...)
So many (#) of possibilities
I hope this makes sense (I think that's the correct method in order to solve it, but I have no idea)
I'm just downright confused
OLL
PLL
F2L
U Perm
F3L skips
8 LLL = 4 L OLL, 4 L PLL
4 LLL = 2 L OLL, 2 L PLL
3 LLL = 2 L OLL, 1 L PLL
2 LLL = 1 L OLL, 1 L PLL
I mean really now
What is the process, from beginning to end, to solving the cube? Please describe the process and all the possibilities. If you could provide links for all the algs necessary that would be great.
For example>
Step 1
(What are we trying to accomplish before moving to the next step)
Bottom cross
Step 2
(What are we trying to accomplish before moving to the next step)
Bottom corners with respective edges (Fridrich method) (Link)
Step 3
(What are we trying to accomplish before moving to the next step)
Orient Last Layer (OLL)
(Link)
Difference between methods (2 look, 4 look, etc...)
So many (#) of possibilities
Step 4
(What are we trying to accomplish before moving to the next step)
Permutate Last Layer (PLL)
(Link)
Difference between methods (2 look, 4 look, etc...)
So many (#) of possibilities
I hope this makes sense (I think that's the correct method in order to solve it, but I have no idea)
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