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[Help Thread] Square-1 Discussion

Ok I'll say it again, I said the same thing he did so it wouldn't be confusing.

When I say double parity on squan everybody knows what I'm talking about.
That's opp/opp. I had no clue what that ones until you put it into 3x3 notation. It's much easier to refer to the ep cases in the format top/bottom instead of referring to it as something like "H perm but with and adj swap and parity on bottom". Instead of saying that you can just say W opp
 
That's opp/opp. I had no clue what that ones until you put it into 3x3 notation. It's much easier to refer to the ep cases in the format top/bottom instead of referring to it as something like "H perm but with and adj swap and parity on bottom". Instead of saying that you can just say W opp
I'm not exactly sure where I said anything about H perms or Adj swaps but when I say double parity I don't mean literally double parity. I mean you have cases impossible to get on a 3x3 on top and bottom (which is double parity to the squan newcomer).

And I didn't put anything into 3x3 notation in that post so I'm not sure what you're referring to.
 
I'm not exactly sure where I said anything about H perms or Adj swaps but when I say double parity I don't mean literally double parity. I mean you have cases impossible to get on a 3x3 on top and bottom.
well the problem with that is there are different swaps you can to do fix parity. I know only 2 being adj and opp but before csp was invented it was not uncommon to know things like W/solved and O/solved. The most commonly known parity is the adj case and doing that twice will yield Z or ajd/adj
 
well the problem with that is there are different swaps you can to do fix parity. I know only 2 being adj and opp but before csp was invented it was not uncommon to know things like W/solved and O/solved. The most commonly known parity is the adj case and doing that twice will yield Z or ajd/adj
All I'm saying is do M2 U2 M2 and you will no longer have double parity.

Why are you bringing up single parity cases?
 
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This alg is impossible in cubeshape, someone fill me in on this double parity (If its a z perm just say z perm)
I'm pretty sure it's Z perm.
I used Z3Cubing's tutorial for squan, and I know that double parity = no parity, but how would I solve that using the info in his tutorial? Or would I have to just learn an alg for that?
You can do 1 U-perm (from Z3) to solve a piece, then just do finish like normal.
Rotations don't change the shape... Do you mean slice?
 
I challenge the relevancy of this argument, all I'm saying is do M2 U2 M2 and you will no longer have double parity
I challenge the relevancey of this case name. All I'm saying is use proper EP names. This is getting a bit drawn out but for the sake of making things clear while posting in this thread please use the EP names found here http://algdb.net/puzzle/sq1/ep

And I'm referring to single parity cases because they are the only parity cases. Double parity cases are just non-parity ep cases
 
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I challenge the relevancey of this case name. All I'm saying is use proper EP names. This is getting a bit drawn out but for the sake of making things clear while posting in this thread please use the EP names found here http://algdb.net/puzzle/sq1/ep
I said use M2 U2 M2 (Opp/Opp) to "fix" double parity, so that a person new to square-1 would understand what the alg would do instead of telling them a seemingly nonsense phrase like Opp/Opp and hoping they understand, this is a help thread not a "go look up the cubing lingo and do your own research which defeats the purpose of a help thread" thread.

PS you spelled relevancy wrong
 
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Here we go for the third time, I said use M2 U2 M2 (Opp/Opp) to "fix" double parity, so that a person new to square-1 would understand what the alg would do instead of telling them a seemingly nonsense phrase like Opp/Opp and hoping they understand, this is a help thread not a "go look up the cubing lingo and do your own research which defeats the purpose of a help thread" thread.
Here we go for the 4th time, I said double parity does not exist because it doesn't. A person new to square-1 should learn what a phrase like Opp/Opp means so they are able to efficiently communicate and understand what algorithms do what. This is a help thread and I linked the lingo in my last post if you could not tell. The page I linked shows you what each EP case I was referring too looks like and a simple click would give you the information you need to understand what I was talking about.
 
Here we go for the 4th time, I said double parity does not exist because it doesn't. A person new to square-1 should learn what a phrase like Opp/Opp means so they are able to efficiently communicate and understand what algorithms do what. This is a help thread and I linked the lingo in my last post if you could not tell. The page I linked shows you what each EP case I was referring too looks like and a simple click would give you the information you need to understand what I was talking about.
He asked, I responded, and you made it overly complicated.
 
K guys, don't make this the 4th parents took cubes thread. @NevEr_QeyX made it understandable for beginners, and @Sub1Hour corrected it with the correct term.
Thank you. I simply made a simple correction with the correct terminology. I'm not here to start a flame war or piss anyone off. I'm just trying to give the best advice that I can and knowing the correct terminology can be very useful as a beginner
 
Side note: I fell like all heated arguments happen when the majority of people are offline
Yeah it's 1 AM for me in America and since Americans are most of the membership the timezones will be slightly different, but pretty much all done part of night. Also explains the heat.
 
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What is the best way to solve Adj-Parity when it appears into the bottom layer?

What I do is: I put the edges in (FD)-(RD), and move to the top layer with: (1,0) / (2,0) [PARITY] (-2,3) /

FD -> Down layer, front side
RD -> Down layer, right side

When it appears in the up layer, I usually take around 6~7 seconds to solve the parity.
But when it is in down layer, I usually take 9~10 seconds.

This is very annoying...
 
What is the best way to solve Adj-Parity when it appears into the bottom layer?

What I do is: I put the edges in (FD)-(RD), and move to the top layer with: (1,0) / (2,0) [PARITY] (-2,3) /

FD -> Down layer, front side
RD -> Down layer, right side

When it appears in the up layer, I usually take around 6~7 seconds to solve the parity.
But when it is in down layer, I usually take 9~10 seconds.

This is very annoying...
It's better to put it in RD BD and slice it to RU and FU then parity 0,3 undo slice
 
What is the best way to solve Adj-Parity when it appears into the bottom layer?

What I do is: I put the edges in (FD)-(RD), and move to the top layer with: (1,0) / (2,0) [PARITY] (-2,3) /

FD -> Down layer, front side
RD -> Down layer, right side

When it appears in the top layer, I usually take around 6~7 seconds to solve the parity.
But when it is in down layer, I usually take 9~10 seconds.

This is very annoying...
Yes that is the best way to do it but I find it faster to do ADF before parity so if you do (1,0) / (2,3) as your setup it could be faster. You could adj adj into but its easier to just slice into it like you do (with a very nice finger drag that flows right into the parity algorithm if you drag with right hand and start with a down slice). Great job on using setup moves, they are useful for PBL because of how you can often do 3x3 plls on square-1 by doing 2 J perms or N perms, but thats a very advanced technique im trying to implement.
 
I am learning CSP right now and I was wondering what moves during cubeshape change the parity from even to odd. For example, if you make a slice involving 3 corners on one layer and 3 on the other changes the parity from even to odd. What piece combinations "Swap" party?
 
New 3 look method because who even needs OBL and PBL? I present to you, CSP, CBL, EBL! It could work but recog would be even harder then it is for standard 3 look solves. Also, the guy that told me to get good and learn algs is making a trainer app that specifies in alg sets and he is working on an OBL trainer. You might know him as the WCA delegate Calvin Nielson who is currently ranked 17 in the world for square-1 single and 23 in the world for square-1 average (and ranked number 1 for keeping me from getting my first gold medal) so he knows what he is talking about, See video here about his app that is currently in the works

 
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