Robert-Y
Member
Gabriel Dechichi sent me an email an hour ago, asking a few questions about the last 6 edges. Somehow I misread his email at first and came up with this idea for solving the last 6 edges. It's fairly straight forward, the only real trouble is the recognition I think.
1. Separate edges into the correct top or bottom layer (as well as the centres). I'll call this SL6E (Separation of the last 6 edges)
2. Solve the last 6 edges (and the centres obviously). I don't have a name for this sub step yet.
I think there are at most 216 cases but it reduced down a lot. Here is a list of all possible bottom layer edge situations:
A. Solved (30 cases including solved)
B. FD needs to be flipped (24 cases)
C. BD needs to be flipped (24 cases)
D. FD and BD need to be flipped (30 cases)
E. FD and BD need to swapped (30 cases)
F. FD needs to be flipped, FD and BD need to swapped (24 cases)
G. BD needs to be flipped, FD and BD need to swapped (24 cases)
H. FD and BD need to be flipped and swapped (30 cases)
The C set is the same as the B set + y2/D2. The G set is also the same as the F set + y2/D2. So you can avoid learning 48 algs if you run into a C or G case, by doing y2/D2, a B or F set alg, then undo y2/D2. Also, you can also influence the D layer edges whilst finishing the CMLL, in order to avoid certain cases. But I haven't experimented with this much.
Example solves:
1.
Scramble: M' U M' U2 M2 U' M U' M' U2 M' U2 M2 U M U2 M2 U' M2 U2
SL6E: U' M2
Finish: M' U M' U M2 U M U2 M' U'
2.
Scramble: M' U' M U2 M U' M2 U' M U' M' U' M2 U M' U' M2 U2 M U
SL6E: M
Finish: U' M' U2 M' U2 M U' M' U' M2 U'
3.
Scramble: M2 U2 M U2 M2 U M' U M U' M' U M' U' M2 U' M' U2 M2 U'
SL6E: U M' U2 M'
Finish: M' U' M' U' M U M' U' M' U M2 U M
4.
Scramble: M2 U2 M' U2 M U2 M' U' M' U2 M' U' M U M' U2 M U M' U'
SL6E: M2 U M'
Finish: U2 M' U M' U M' U' M' U M U' M' U'
5.
Scramble: M' U2 M2 U' M U2 M' U M' U2 M U2 M' U M2 U' M2 U2 M U
SL6E: M2 U M
Finish: D2 M' U' M' U2 M2 U M U2 M' D2
1. Separate edges into the correct top or bottom layer (as well as the centres). I'll call this SL6E (Separation of the last 6 edges)
2. Solve the last 6 edges (and the centres obviously). I don't have a name for this sub step yet.
I think there are at most 216 cases but it reduced down a lot. Here is a list of all possible bottom layer edge situations:
A. Solved (30 cases including solved)
B. FD needs to be flipped (24 cases)
C. BD needs to be flipped (24 cases)
D. FD and BD need to be flipped (30 cases)
E. FD and BD need to swapped (30 cases)
F. FD needs to be flipped, FD and BD need to swapped (24 cases)
G. BD needs to be flipped, FD and BD need to swapped (24 cases)
H. FD and BD need to be flipped and swapped (30 cases)
The C set is the same as the B set + y2/D2. The G set is also the same as the F set + y2/D2. So you can avoid learning 48 algs if you run into a C or G case, by doing y2/D2, a B or F set alg, then undo y2/D2. Also, you can also influence the D layer edges whilst finishing the CMLL, in order to avoid certain cases. But I haven't experimented with this much.
Example solves:
1.
Scramble: M' U M' U2 M2 U' M U' M' U2 M' U2 M2 U M U2 M2 U' M2 U2
SL6E: U' M2
Finish: M' U M' U M2 U M U2 M' U'
2.
Scramble: M' U' M U2 M U' M2 U' M U' M' U' M2 U M' U' M2 U2 M U
SL6E: M
Finish: U' M' U2 M' U2 M U' M' U' M2 U'
3.
Scramble: M2 U2 M U2 M2 U M' U M U' M' U M' U' M2 U' M' U2 M2 U'
SL6E: U M' U2 M'
Finish: M' U' M' U' M U M' U' M' U M2 U M
4.
Scramble: M2 U2 M' U2 M U2 M' U' M' U2 M' U' M U M' U2 M U M' U'
SL6E: M2 U M'
Finish: U2 M' U M' U M' U' M' U M U' M' U'
5.
Scramble: M' U2 M2 U' M U2 M' U M' U2 M U2 M' U M2 U' M2 U2 M U
SL6E: M2 U M
Finish: D2 M' U' M' U2 M2 U M U2 M' D2
Yes I realise it's 4am and I have a competition in 5 days...