Random Blindfold Cubing Discussion

[AbstractAlg]

Has anyone tried this for 4BLD edges?

1. Define half of each of the 12 edges to be solved.

2. Solve the other 12 edge pieces so they match up with the "solved" 12 using commutators or whatever.

3. Solve the edges like it's a 3BLD based on the initial positions of the "solved" edges.

That sounds terrible to me.
So you define solved and memo others, but knowing which ones are already solved, than memoing edge pairs for 3x3 reduction style phase. I would just memo 24 edges and that's it.

 

[Noahaha]

That sounds terrible to me.
So you define solved and memo others, but knowing which ones are already solved, than memoing edge pairs for 3x3 reduction style phase. I would just memo 24 edges and that's it.

The same 12 would be the solved ones every time. It's basically just solving 12 edges 4x4 style and 12 3x3 style instead of 24 4x4 style.

 

[bobthegiraffemonkey]

Wouldn't always work using set edges (as far as I can tell, I'm thinking of two possible interpretations of this but there may be more ways of doing it), since it depends on how the edges are paired. Using set wing positions as fixed and solving around them, two fixed positions may contain both wings of the same edge. Using a fixed wing from each edge might give you two if these fixed wings paired with each other, which would at the very least be awkward I think. Figuring it out on a per solve basis could be fun though, might try it and see if I can manage it.

 

[A Leman]

The same 12 would be the solved ones every time. It's basically just solving 12 edges 4x4 style and 12 3x3 style instead of 24 4x4 style.

The difference is that the targets would be different from the color scheme of the stickers for the first part and the 3x3 phase would need a different journey.Not at all worth it in my opinion.The different color scheme part would complicate my memo.

 

[TMOY]

The same 12 would be the solved ones every time.

And how do you deal with the case where two of your 12 "always solved" edges are paired together ?

 

[jonlin]

And how do you deal with the case where two of your 12 "always solved" edges are paired together ?

You got a skip. Yay.

 

[JonnyWhoopes]

You got a skip. Yay.

I think he's asking what would you do if one of your always solved edges belongs in DFr, and another of your solved edges belongs in DFl. What then?

 

[Noahaha]

I think he's asking what would you do if one of your always solved edges belongs in DFr, and another of your solved edges belongs in DFl. What then?

That would be a huge problem lol.

 

[Jaycee]

For UBL -> FRD -> RUB :

f d R2 U' r' F R2 F' y

Probably no good, I just randomly found it by hand xD Yes, I'm aware this must be just another form of a well known alg.

EDIT : I'm just going to use y U L' U' R' U L U' R even though I really like the one I found.

 

[jonlin]

That would be a huge problem lol.

Shoot to a new cycle.

 

[Noahaha]

Shoot to a new cycle.

Wouldn't work either, since those edges are supposed to stay foxes so they'll never be paired.

 

[Jaycee]

Am I the only one who thinks that when you're finding comms to use, finding an A9 gives the most satisfying feeling?

EDIT : Even better finding 2 in a row!

 

[Noahaha]

Am I the only one who thinks that when you're finding comms to use, finding an A9 gives the most satisfying feeling?

EDIT : Even better finding 2 in a row!

Definitely.

 

[RyanReese09]

Well half the time, A9 is the fastest one.

 

[drewsopchak]

Am I the only one who thinks that when you're finding comms to use, finding an A9 gives the most satisfying feeling?

EDIT : Even better finding 2 in a row!

Most of the time, I just perform "A10s"

 

[Ickathu]

Most of the time, I just perform "A10s"

A10s are almost my favorite. I really like the 14 movers... Yeah...
ULB>RFD>LDF
z2 F R2 U R2 U' R2 D' R2 U R2 U' R2 D F' z2

ULB>RFD>DBL
y2 B D' R2 U R2 U' R2 D R2 U R2 U' R2 B' y2

Better algs por favor?

 

[Jaycee]

ULB>RFD>LDF
z2 F R2 U R2 U' R2 D' R2 U R2 U' R2 D F' z2

ULB>RFD>DBL
y2 B D' R2 U R2 U' R2 D R2 U R2 U' R2 B' y2

Better algs por favor?

x' [R: [R U' R', D2]] x = x' R2 U' R' D2 R U R' D2 l'

[D: [L2, U R' U']] = D L2 U R' U' L2 U R U' D'

 

[bobthegiraffemonkey]

ULB>RFD>LDF

x R2 D' R' U2 R D R' U2 R' x'

ULB>RFD>DBL

(x' y') R U2 R D' R' U2 R D R2' (y x)

That's what I would do anyway.

 

[RyanReese09]

For UBL RFD DBL, I'd do

y U R2 U L' etc

Most rotations are slow for me.

 

[Noahaha]

A10s are almost my favorite. I really like the 14 movers... Yeah...
ULB>RFD>LDF
z2 F R2 U R2 U' R2 D' R2 U R2 U' R2 D F' z2

ULB>RFD>DBL
y2 B D' R2 U R2 U' R2 D R2 U R2 U' R2 B' y2

Better algs por favor?

LDF - [L : [R U2 R', D2]]

DBL - [D : [L2, U R' U']]

A10s ftw! I really like both of these btw.

EDIT: Did I start this RFD trend? Lol.