Berd
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Whats the odds of an X-cross skip in Yau? XX-cross!?
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oh god I'm an idiotThe edges can be flipped, though.
No, actually. The probability of that outcome is 100%. To conclude that it is less you would have to ignore a fact already stated in the premise.Nah, it's far less likely that you get the 4x4 scramble that you get next, and that will happen to you.
No, actually. The probability of that outcome is 100%. To conclude that it is less you would have to ignore a fact already stated in the premise.
Someone who knows math: what are the odds of skipping last slot, OLL, PLL, OLL parity, PLL parity, and AUF on a 4x4?
The probability of skipping last slot, OLL, PLL, OLL parity, PLL parity and AUF is 1 / (150 * 216 * 72 * 2 * 2 * 4) = 1 / 37,324,800
That's almost 3 times less likely than a lotto win in the UK. All things considered, I think I'd prefer the lotto win.![]()
This means that you could be the only person this has ever happened to and will ever happen to in the cubing community.
Few of us will ever experience this skip but some cubers will be lucky enough to get it.
Tens of thousands of people doing hundreds / thousands of 4x4 solves a year adds up to a large number.
That seems like a long time to count to a million. Three months is 8 million seconds. Surely, even including sleep, it doesn't take 8 seconds to say each number?There is a man who did nothing but count to try and break the World Record for the highest number counted to. He slept, obviously, but from the moment he woke up to the moment he went to sleep he counted. After 3 solid months of counting all day, every day, he broke the world record by reaching 1 million.
But 37 million? That number is huge.
tl;dr I would be VERY surprised if I saw another cuber here have the same luck.
You're calculation is based on the WCA people doing it in one year. They have already been solving the 4x4 for many years and they will solve it for many years to come.
There are lots of people who cube for a hobby who don't actually compete, I know several amongst my friends. An example would be someone who does 12 solves on the 4x4 each week for an extended period of time... slightly over 600 solves in a year. You only need 60,000 of those guys (five times the WCA number) to do 37 million solves in a year.
Anyhow this logic is flawed because probability doesn't work in such a simple way. Doing 37,324,800 solves doesn't guarantee the outcome... you can equally say there is approximately 50% chance of the outcome by doing half the number of solves.
I think it unlikely for just one person in the community to have this happen.
Edit: There are 27,207 registered members on this forum.
That seems like a long time to count to a million. Three months is 8 million seconds. Surely, even including sleep, it doesn't take 8 seconds to say each number?
wat
wat
Is there some limit for how slowly you have to count? Because it shouldn't take that long.
Ok, I was wrong then, sorry.Count out loud from let's say 374400 to 374500 and let us know how long it takes you.
Ok, I was wrong then, sorry.
But 37 million? That number is huge.
Just to put this into context - There is a man who did nothing but count to try and break the World Record for the highest number counted to. He slept, obviously, but from the moment he woke up to the moment he went to sleep he counted. After 3 solid months of counting all day, every day, he broke the world record by reaching 1 million.
There are 12,498 people who have ever solved a 4x4 officially in a WCA competition (I'm going to use this number because it isn't too far off the actual number, because people who have never been to competitions and inactive cubers cancel each other out).
The probability of all the events described occurring is 37,324,800. Take that number and divide it by the number of people who have competed.
This would mean that 12,500 people would each have to do ~3000 (2986.46183 to be exact) solves a year for this to happen once in that year.
Now, how long would this take? The median of all people who have competed is 6249, and the time at that number is 1:24.72.
84.72 seconds multiplied by the 37,324,800 times the cube would have to be solved is 3,162,157,056 seconds, or 878,376.96 hours, or 36,599 days (100.5 years total solving time).
For each person that would be 253,013 seconds, or 70 hours.
tl;dr I would be VERY surprised if I saw another cuber here have the same luck.
EDIT- In other words, what you just did IRNjuggle, you had a 0.0000000267918381 chance of doing
Yeah.