PLL order from easiest to hardest

[Ellsming]

That's the one I use, then the three variations of it. For some reason I can't seem to do it fast. I can recognise that it's a G-perm quickly, but then I have to do a few U-turns before I figure out which one, then I often end up doing another U2 if it's one of the mirror algorithms I know. Maybe it's just practice that I need?

 

[TopCuber]

When I learned ful PLL, I did a solve then learned the upcoming case.

 

[tx789]

I hate my alg for N perms but PLL is really really easy

 

[ultimatecuber]

wat u dont find the G-Perm hard?

 

[Ninja Storm]

wat u dont find the G-Perm hard?

Honestly, the G-Perms aren't hard when you know how to fingertrick them. I find them to be some of my favorite, actually.

 

[ultimatecuber]

but how do u recognise them?

 

[Youcuber2]

but how do u recognise them?

Look for a 2x1 block and a set of headlights. For a more specific answer, there are some good videos out there about recognizing g perms.

 

[kcl]

I like any that are ELLs too. Roux isn't my main but m slices yo..

 

[ultimatecuber]

thanks but i already know how to recognise them
wat i meant was
how do u differentiate one G-Perm from the other
it takes me around 5 secs to do so
and considering that 5 secs is the WR
thats not so fast

 

[applemobile]

Practice

 

[YddEd]

I think the easiest for me was the T perm. Hardest is probably Z perm. The dumb alg hated me so I made up my own.

 

[JasonK]

thanks but i already know how to recognise them
wat i meant was
how do u differentiate one G-Perm from the other
it takes me around 5 secs to do so
and considering that 5 secs is the WR
thats not so fast

Put the headlights on the left. Each of the G-perms will have the 2x1 block in a different place. That's how you differentiate them. Being able to do that quickly just comes with practice.

 

[ben1996123]

thanks but i already know how to recognise them
wat i meant was
how do u differentiate one G-Perm from the other
it takes me around 5 secs to do so
and considering that 5 secs is the WR
thats not so fast

let f(x) be a function that returns pll x so A=f(g) is a g perm

\( \frac{dA}{dx}=f'(g) \)

dun stop typeing u instead of you csch its annoying ! ! !
you donut need to put a
line break every few words
either

 

[KongShou]

Let f(x) be a function that returns a g perm
f(Ga) would be a g perm and = 2x1+ headlight

Simply do f'(Ga) with respect to x
f'(2x1) = f'(2x) = 2
f'(headlight)= aedgh^2lti= 0

get 2+0= 2

f'(Ga) = 2

You can also do the same thing with all other g perms and even all PLLs and OLLS too
Easy

 

[qqwref]

Hold the headlights on left. Then there are four possible places the 2x1 block can be, and each one is a different G perm. It can be on the back, on the right pointing towards the back, on the right pointing towards the front, or on the front.

 

[ultimatecuber]

thanks for the advice everyone