rjohnson_8ball
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- Apr 17, 2008
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(RLD2R'L'D)2 is the simpliest.
That is the one I use. If you perform the commutator [ [R L, D2], D ]
and apply an extra D2 afterward, you get
((R L D2 L' R' D2) D (D2 R L D2 L' R') D' )(D2)
which is (R L D2 L' R' D)*2. Did I do it okay?