Welcome to the Speedsolving.com, home of the web's largest puzzle community! You are currently viewing our forum as a guest which gives you limited access to join discussions and access our other features.

You could always set it up as the 4x4 "OLL parity" which switches two edges (e.g. l' D2 l and then do the OLL parity to "flip" the UB edge. Just be aware that the alg changes U centers around). Or try this alg Lucas gave me that I never bothered to learn: r' U2 r2 U2 r U2 r U2 l r2' U2 r' U2 r U2 l' U2

What you're looking for doesn't actually exist: commutators can't solve two-cycles. But if you just want an algorithm, the one shelley gave is fine Way better than what I'd use, anyway.

It's impossible to have a commutator do this, because it is an odd cycle. However, I would use this alg if you are allowed to rotate the U center 180 degrees.

D R F' l' U2 l' U2 F2 l' F2 r U2 r' U2 l2 F R' D'

Chris

--edit--
sorry Shelley, I skimmed this thread too quickly, beaten to the punch ;-) Shelley's alg is shorter and more execution friendly than mine, so I recommend to use hers instead.

It is possible to solve it using commutators. Just do r or r' first then it will work. Problem is that you also have to commutate the edges of the r-slice back into their original places.

OK, then I got a tricky but short one (alg, not commutator) that I just made up:

F2 r (y) M2 (y) U2 l' U2 l U2 r' U2 r (x') U2 r D2 r' U2 (x')

Looks long because of all orientations but it is "only" 16 turns. Remove first and last move, that are setup + restore, and it swaps two diagonal LL edges.