Mirroring algorithms vs. right hand dominant algorithms

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Feb 8, 2013
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WCA ID
2013HALL03
So I'm relatively new to speedcubing and I'm just about done learning full PLL. I've noticed that, at least on the site I've been using http://www.cubewhiz.com/pll.php, more often than not there's a different algorithm for a mirrored situation. For example, there are two completely different J perm algorithms and a few different G perms.

In an effort to cut down on how much I have to learn I've just been mirroring the algorithms on the left side for cases such as the J perms. Why is this not the norm? Is there a significant speed advantage to using your right hand for as much as possible?
 
Some people are quite right hand dominant so it's more comfortable to use a different algorithm for the mirror case instead of trying to do everything with the left hand. If you are fairly ambidextrous then good for you and you can mirror the case with your left hand just as fast as with the right hand. It really depends on what's comfortable for each person.
 
I know. I've been mirroring the algorithms in order to deal with both cases so I don't have to learn new ones. My question is why would there be a different algorithm altogether when mirroring handles the cases.

I mirrored most of my algorithms due to laziness. However, a lot of algorithms are hard to perform if your other hand isn't as dexterous. For example, all of my left-face dominant algorithms are slower than their right-face mirrors (particularly R perm). My left hand is awkward and I usually need to shift my grip on the cube to begin execution.
 
I guess that makes sense. I'm fairly ambidextrous to begin with so it's not a huge problem for me. I just figured that it would be in a speedcubers interest to be able to use both hands so as to rest the right hand every now and then.
 
I've always been fairly ambidextrous in cubing (with training). I also mirror all of my algorithms, and for some of my algs like T perm and G perm I am actually faster left handed than I am right handed (I've done time trials to test this, this is not anecdotal or by a "feeling"). Over the years I have come to realize that this is definitely not the norm, and as a general rule people I meet in competitions think it is unusual when they hear that I do this.

It works for me. If it works for you too I say stick with it. With enough practice, you may find that some of your algs will become even faster left handed than right handed.
 
I'm left handed but since all the algs I found when I started cubing were made for right handed people me right hand has completely taken over and even if the algs a mirror it's like learning a whole new one
 
Question

I know how to mirror algs. but if the alg. applies to front right, (and I mirror it)does it go to front left? Also, do I turn my cube to the back side to finish, or is there a way to solve only with front face.
 
Next time, please put more than "Question" in the thread title.

The pieces the mirrored alg affects depends on the direction of mirror (U/D, L/R, F/B).
Take a Sune case, for example:

and an Antisune case:


The Sune OLL case can be solved using the algorithm R U R' U R U2 R'.
The Antisune case, as pictured, is a mirror of the Sune case above from left to right. That is, every aspect of the OLL from the right side is mirrored to the left, and vice versa.
Thus in this case, the algorithm to solve the Antisune OLL from the angle pictured is the left to right mirror (L/R mirror) of any algorithm that solves the Sune OLL from the angle pictured.
Thus, R U R' U R U2 R' becomes L' U' L U' L' U2 L.

However, if the Antisune OLL case looked like this:

Now we have to reevaluate the type of mirror because of the difference between the angle of this Antisune and the one previously (a y2/U2).
Comparing to the Sune pictured, this second Antisune case is a mirror of the Sune case from front to back. As before, every aspect of the OLL from the front side is mirrored to the back, and vice versa.
So for this case, the algorithm to solve the Antisune OLL from the angle pictured is the front to back mirror (F/B mirror) of any algorithm that solves the Sune OLL from the angle pictured.
Thus, R U R' U R U2 R' becomes R' U' R U' R' U2 R.

As for the other part of your post, I have no idea what you're trying to say, sorry.

Hope this helps.
 
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