Mathematics Question (quite easy)

Brian Le

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Jan 22, 2008
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I know this question is easy and stupid, but I really need to confirm this.

The formula for direct variation is y = k/x. You have the equation x = 5y. Tell whether x and y show direct variation, inverse variation, or neither.

To find out what variation the equation shows, y must be isolated. To do that, we divide each side by 5, giving us y = x/5. Thus, x and y show direct variation. Why is that? Is it because x is not in denominator?
 
As far as I've always understood it, if x is in the numerator it's direct, if it is in the denominator, it's indirect. That's because it is directly part of the multiplication of y when in the numerator, but not so if in the denominator.


If that's incorrect or unclear please correct me/elaborate.
 
The formula for direct variation is y = k/x.
Sure? As one goes up, the other goes down. That sounds like inverse to me. :p

You have the equation x = 5y. Tell whether x and y show direct variation, inverse variation, or neither.
Well, direct. Each varies directly and constantly depending on variation of the other.


To find out what variation the equation shows, y must be isolated. To do that, we divide each side by 5, giving us y = x/5. Thus, x and y show direct variation. Why is that? Is it because x is not in denominator?
Sorta. Consider it y=x*(1/5), which is really y=kx for k=1/5.

Isolting the y (especially in more difficult problems) allows you to see what y does compared to (i.e. as a function of varying) x.

Direct: y = kx , y goes up with x.
Inverse: y = k/x , y goes down as x goes up (and vice-versa).
Neither: y=0; y doesn't depend on x. Or, say y=sin(x). x doesn't go anywhere, really. :p


(Note: I'm assuming k>0)
 
Opps, sorry about stating that y = k/x was direct. It's inverse, ahaha.

Anyway, thanks Lucas!
 
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