intuitive SQ-1 parity

Or alternatively:
2'. Do 1/6th of a turn in either direction (6-cycle of corners => odd parity)
Right. Though, this needs the six corners on top or bottom, which I think takes slightly longer to set up.

Six easy corners on the left hand side..
Two more on the right... turn the puzzle over...
Nice... that is a surprisingly accurate description! (except that only half of the puzzle should be turned over, but that should be clear... oh and the song started with the right)
 
Parity on square-1 is the same thing- an odd number of two swaps.
Would you mind taking out that "two" and just say "odd number of swaps"? Cause typically two swaps involve four pieces and I'm quite sure that's not what you mean. At the very least, write "two-swaps", though I find that ugly.
 
Or alternatively:
2'. Do 1/6th of a turn in either direction (6-cycle of corners => odd parity)
Right. Though, this needs the six corners on top or bottom, which I think takes slightly longer to set up.
It takes only one extra twist. And contrary to the slightly shorter solution, it doesn't break the middle layer parity, which may be useful.
 
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