JL58
Regular
- Joined
- Dec 15, 2008
- Messages
- 127
You have at least one cycle, the one you start with. All others are "additional." (or total number of cycles -1)
So if I count 12 edge shoots, in 3 cycles, that is 12 - (3-1) = 10. I miss 1. Therefore I look for either
- an edge already in place to complete the count or
- a new cycle of 1 (a flipped edge)
In the first case I have 12 shoots - (3-1) additional cycles + 1 in-place = 11
In the case of a flipped edge I have 14 shoots, 4 cycles (i.e. 3 additional) and no in-place edge: 14 - 3 = 11. I'm done.
Of course I could count all cycles and reach for counts of 10 and 6 instead of 11 and 7. But I tend to remember the additional ones better: these are the cycles that you have to break by moving your buffer piece into them. Just a personal preference I guess. Hope it helps.
So if I count 12 edge shoots, in 3 cycles, that is 12 - (3-1) = 10. I miss 1. Therefore I look for either
- an edge already in place to complete the count or
- a new cycle of 1 (a flipped edge)
In the first case I have 12 shoots - (3-1) additional cycles + 1 in-place = 11
In the case of a flipped edge I have 14 shoots, 4 cycles (i.e. 3 additional) and no in-place edge: 14 - 3 = 11. I'm done.
Of course I could count all cycles and reach for counts of 10 and 6 instead of 11 and 7. But I tend to remember the additional ones better: these are the cycles that you have to break by moving your buffer piece into them. Just a personal preference I guess. Hope it helps.
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