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Erm, it's "less" not "lesser", and "algorithm" should be plural. Also, you're only comparing two, so it's "faster", and it's "Fridrich".
Anyway, I think the idea of Roux F2L and OLL+PLL would be faster.
Bad, bad idea!Anyway, I think the idea of Roux F2L and OLL+PLL would be faster.
Agreed. If you want Fridrich, use Fridrich. Continuing that way after the 1x2x3 blocks is very unnatural.Bad, bad idea!Anyway, I think the idea of Roux F2L and OLL+PLL would be faster.
Agreed. If you want Fridrich, use Fridrich. Continuing that way after the 1x2x3 blocks is very unnatural.Bad, bad idea!Anyway, I think the idea of Roux F2L and OLL+PLL would be faster.
If I knew OLL and not Roux, I would still say that it's an unnatural idea. CMLL is a very logical continuation, after that you can still move M and U freely. It takes advantage of the situation. But solving DF and DB seems very clumsy to me, like a too late attempt to go back to Fridrich with "F2L" and "LL". It doesn't fit Roux at all.That's not true. It's only "unnatural" if you've already learned all of one or the other and feel familiar with only the one.
In Petrus, F2L and LL are very individual steps. You can use whatever method you want for LL.Hybrid methods are not bad. No one's complained about Petrich or Fridrus, or whatever.
Erm, it's "fewer," not "less."Erm, it's "less" not "lesser", and "algorithm" should be plural. Also, you're only comparing two, so it's "faster", and it's "Fridrich".
Anyway, I think the idea of Roux F2L and OLL+PLL would be faster.
Depends on what that means exactly.... but you can't deny that it would work.
I am a bit impatient. I feel that I won't get any better on friedrich. My average out of 12 is about 21 sec. Thats why I was wondering if it was worth learning roux.
I am a bit impatient. I feel that I won't get any better on friedrich. My average out of 12 is about 21 sec. Thats why I was wondering if it was worth learning roux.
Haha, 21 seconds is no where near the limit of Fridrich. All the sub-10 solves use Fridrich I bet.