Freestyle Blindfold corner algs

[McWizzle94]

How do you go about making upyour own commutators?

If you're asking this you're not getting it. Some people find defining a 'lone corner' and an 'interchangeable pair of corners' makes sense, but basically:
1. Put a corner from one layer into the opposite layer, without affecting any other pieces in that layer. eg. L D L' puts the FLD corner into FUL spot. No other U layer pieces are affected.
2. Now any U move will change that corner for another. eg U2. These moves form A and B of the commutator. For my example, A = L D L', B = U2. Now put together ABA'B' for a 3 cycle.
That's science. Well, group theory. Which is maths. Meh. Turns out *most* cycles can be done this way. Some need more nifty A algorithms which insert a corner into a layer.

How many moves are they usually?

Corners: 8-12 moves. Try to get setup moves cancelling the last move of B'.

How would you know while during the memo when your going to have a parity.

I have no idea. I've never memorised a 3x3x3. I can't blindsolve. Something to do with an odd number of pieces in the cycle. Ask a pro.

And what is the parity or parities for freestyle corners?

Hmm. Again showing your hand by asking an odd question... BLD parity is when the edges and corners cannot be solved independently as there is a 2-edge, 2-corner swap (kinda like a T perm for example) somewhere. This means the usual BLD trick of treating corners and edges separately for memo and solving can't work. Your memo falls short and you have to remember to perform some sort of edegey-cornery swap at some point. I recommend some set-up moves and a LL perm like T. You'll pop it if you're anything like me.

Again, I'm a nobody who has only ever solved a 2x2x2 blind, only done it once, and it was lucky. (2 ready placed pieces or something) So act upon my advice with care.

Sorry to be off-topic but that word is now officially in the dictionary!

anyway, you did a good job of explaining things here. About the parity question during memo, if you find when memorizing corners that you have one left, you have parity. What this means is after cycling all of the other corners, you will end up were the last corner and the corner you start with have to switch. You will also have the same thing with the edges. The way I solve it is I reduce the cycles so that only 2 edges and 2 corners need to be swapped, and then I use a set-up move, a PLL, and then undo the set-up move.

 

[Escher]

i lol'd at your comment about the t-perm ewan

 

[c9m9h9]

so i recently learned M2R2 and im around 4 minutes with it, if i switched to 3 cycle corners do you guys think it would improve my time?

 

[joey]

Nope. Nope.

 

[boiiwonder]

How do you go about making upyour own commutators?

If you're asking this you're not getting it. Some people find defining a 'lone corner' and an 'interchangeable pair of corners' makes sense, but basically:
1. Put a corner from one layer into the opposite layer, without affecting any other pieces in that layer. eg. L D L' puts the FLD corner into FUL spot. No other U layer pieces are affected.
2. Now any U move will change that corner for another. eg U2. These moves form A and B of the commutator. For my example, A = L D L', B = U2. Now put together ABA'B' for a 3 cycle.
That's science. Well, group theory. Which is maths. Meh. Turns out *most* cycles can be done this way. Some need more nifty A algorithms which insert a corner into a layer.

How many moves are they usually?

Corners: 8-12 moves. Try to get setup moves cancelling the last move of B'.

How would you know while during the memo when your going to have a parity.

I have no idea. I've never memorised a 3x3x3. I can't blindsolve. Something to do with an odd number of pieces in the cycle. Ask a pro.

And what is the parity or parities for freestyle corners?

Hmm. Again showing your hand by asking an odd question... BLD parity is when the edges and corners cannot be solved independently as there is a 2-edge, 2-corner swap (kinda like a T perm for example) somewhere. This means the usual BLD trick of treating corners and edges separately for memo and solving can't work. Your memo falls short and you have to remember to perform some sort of edegey-cornery swap at some point. I recommend some set-up moves and a LL perm like T. You'll pop it if you're anything like me.

Again, I'm a nobody who has only ever solved a 2x2x2 blind, only done it once, and it was lucky. (2 ready placed pieces or something) So act upon my advice with care.

Thanks For the bold print. That helped.

 

[MatsBergsten]

>>

Okay I have a few questions

>> How would you know while during the memo when your going to have a parity.

Simply when you have an odd number of edges (and corners) in your solving
cycle. Then whether you solve it with M2R2 or commutators or some other
way does not matter.

Mats

 

[joey]

Oh my, I told him to check the forums! And he did

 

[Jacco]

I've started learning to use commutators for corners and I really like it.
I'm sorry if I missed this, but what is a nice commutator for UBR -> RDB -> LDB?

 

[cubeRemi]

I've started learning to use commutators for corners and I really like it.
I'm sorry if I missed this, but what is a nice commutator for UBR -> RDB -> LDB?

F'UFD2F'U'FD2 would be nice, 8 mover. or U (RUR') D2 (RU'R') D2 U'


freestyle in Nederland, jhee!!!

Remi

 

[Jacco]

Eej, thanks, maar dat cycled BRU -> RDF ->LBD.

 

[cubeRemi]

if you 'screamble' D2F'UFD2F'U'F you wil have to solve the cycle: UBR -> RDB -> LDB
you can solve this with the inverse screamble: F'UFD2F'U'FD2

or U (RUR') D2 (RU'R') D2 U'

you have to perform the solution twice in order to see what it will do

Remi

EDIT: http://dbeyer.110mb.com/BHcorners.txt

hier zie je alle mogelijke cases met één oplossing per case (terwijl er zijn soms meerdere even lange oplossingen zijn).

 

[Jacco]

Thanks.


(maar die algs zijn nog steeds voor andere cycles =p)

 

[fanwuq]

I just had the weirdest Freestyle corners in one of my solves last night. I wasted about extra 20s that if I had used classic Pochmann, but I think it was worth it.

Solution was:
D y2 Accw y2 D' to solve LDF, LBU, RBU corners
Flip FUR and FUL corners using right sune, left sune.
Flip LBU, RDF, RBD by using R2 Sune U' Uccw U' R2
Solve the edges
U'F2UM2U'F2U for parity
D2F2y2 R-perm B2D2 to finish LDB and RDB corners.

Such a strange solution. As free as it gets for me.

 

[martijn_cube]

Can anybody look at this 3 cycle. can't really get it right.
the way i look at it now, (because of classic pochmann)
i start at Ulb --> Urf --> Rub
I was thinking of starting with U2, to solve the red/green. then do someting to put the orange/blue in that place, then U2 back to solve that piece, and then something back . but i think i need to do a setup move or something.




I have this one from the Corner list: y L2 (B2L'F2) L (B2L'F2) L', but that one doesn't really seem logical yet. doesn't really looks like a commutator.

 

[Pedro]

Can anybody look at this 3 cycle. can't really get it right.
the way i look at it now, (because of classic pochmann)
i start at Ulb --> Urf --> Rub
I was thinking of starting with U2, to solve the red/green. then do someting to put the orange/blue in that place, then U2 back to solve that piece, and then something back . but i think i need to do a setup move or something.

I'd do F to set up
then
[F L2 F', R2]
then F'

so, writing everything, would be F2 L2 F' R2 F L2 F' R2 F'

 

[martijn_cube]

tnx. that's a nice one. has more logic then the one from the corner paige. although it's the same one, from this point it looks different, also because you show the setup move F.

 

[Stefan]

What's with all the F turns and double turns?
F [ R2, U' L' U ] F' = F R2 U' L' U R2 U' L U F'

 

[Pedro]

but mine is 9 moves

 

[Ville Seppänen]

But it's slower. You can also do y R U2 R' B R B' U2 B R' B' which is also 10 moves.

 

[Pedro]

I don't like B moves