Weston
Premium Member
The misuses of "effect" and "affect" are driving me crazy.
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It all depends on what pieces are where.
For the last time, he's saying that the OLL DOES switch around the pieces in some way and that just because that happens, does not mean you will get the same PLL case very time.
unless you know one look last layer.
Who does?
All OLLs can give all PLLs. It's just coincidence.. Depending on what algorithm you use to solve the OLL case, you will get certain PLL cases.
I love how someone (you) actually knows ZBLL now, just for posts like this.I have a one look last layer. >.>
I can actually decide if I want a certain PLL.
(If edges are oriented.)
OMG this is the exact combination I just had yesterday in my record video!
http://www.youtube.com/watch?v=pfqs2rdAkRg#t=25
Still just coincidence.
Do yuo think that the distribution of the PLLs is independent of the OLL you are just executing?
Yeah. I'd summarize it like this:Do yuo think that the distribution of the PLLs is independent of the OLL you are just executing?OMG this is the exact combination I just had yesterday in my record video!
http://www.youtube.com/watch?v=pfqs2rdAkRg#t=25
Still just coincidence.
Let's do this for the 2x2x2 which has fewer and simpler PLLs. The cases and probabilities:Wait, couldn't PLL probabilities be affected? Let's say you get a G perm, you have a 1/9 chance of getting that, with the OLL said before. Now if the way your OLL manipulates the permutation, couldn't that cause a 1/9 for T perms?
Yeah. I'd summarize it like this:Do yuo think that the distribution of the PLLs is independent of the OLL you are just executing?OMG this is the exact combination I just had yesterday in my record video!
http://www.youtube.com/watch?v=pfqs2rdAkRg#t=25
Still just coincidence.
PLL is affected, PLL probabilities are not.
QUOTE]
Just my thougt: A certain OLL gives the probabilities for the following PLLs. Those probabilities are not neccesarily the same as the known probabilities for the different PLLs. Weighting over all OLLs should give the correct value.
Just my thougt: A certain OLL gives the probabilities for the following PLLs. Those probabilities are not neccesarily the same as the known probabilities for the different PLLs. Weighting over all OLLs should give the correct value.