Do OLLs effect which PLL you get?

It all depends on what pieces are where.
For the last time, he's saying that the OLL DOES switch around the pieces in some way and that just because that happens, does not mean you will get the same PLL case very time.

unless you know one look last layer.

Who does?

http://www.worldcubeassociation.org...gionId=&years=&show=All+Persons&single=Single

thats 594 people, officially. Also look at http://www.speedsolving.com/forum/showthread.php?t=3582

I know technically a one look cube but that does include the last layer...
 
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All OLLs can give all PLLs. It's just coincidence.. Depending on what algorithm you use to solve the OLL case, you will get certain PLL cases.
 
All OLLs can give all PLLs. It's just coincidence.. Depending on what algorithm you use to solve the OLL case, you will get certain PLL cases.

Almost correct, but I would add the following:

Depending on what algorithm you use to solve the OLL case and depending on how the LL is permuted before applying any algorithm you will get a certain PLL case.

Different OLL algorithms permute the pieces in different ways, but you can have all kind of permutations (no matter which OLL case you have) before you apply any algorithm.
 
OMG this is the exact combination I just had yesterday in my record video!
http://www.youtube.com/watch?v=pfqs2rdAkRg#t=25
Still just coincidence.
Do yuo think that the distribution of the PLLs is independent of the OLL you are just executing?
Yeah. I'd summarize it like this:

PLL is affected, PLL probabilities are not.

guitardude7241 was right about the first part but apparently didn't understand that the question was about the second part. Yes, obviously one *can* affect the PLL probabilities by choosing an OLL alg depending on PLL, but clearly that's not what Zarxrax had in mind.
 
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Wait, couldn't PLL probabilities be affected? Let's say you get a G perm, you have a 1/9 chance of getting that, with the OLL said before. Now if the way your OLL manipulates the permutation, couldn't that cause a 1/9 for T perms?
 
Wait, couldn't PLL probabilities be affected? Let's say you get a G perm, you have a 1/9 chance of getting that, with the OLL said before. Now if the way your OLL manipulates the permutation, couldn't that cause a 1/9 for T perms?
Let's do this for the 2x2x2 which has fewer and simpler PLLs. The cases and probabilities:

1/6 chance of PLL = solved
1/6 chance of PLL = opposite corners swapped
4/6 chance of PLL = adjacent corners swapped

Pick some OLL algorithm and analyse what it does to the probabilities.
 
Sune: Since mine is 2-gen it won't matter.
Anti-Sune: 2-gen
Double Superman:
Solved-Opposite corners swapped
Opposite corners swapped - solved
Adjacent corners swapped - Adjacent Corners swapped
Adjacent corners swapped - Adjacent corners swapped
Adjacent corners swapped - Adjacent corners swapped
Adjacent corners swapped - Adjacent corners swapped

Ah, I think I get it.
 
Okay, I don't know what the OLL is called but...

Solved - Adjacent
Opposite - Adjacent
Adjacent - Solved
Adjacent - Opposite
Adjacent - Adjacent
Adjacent - Adjacent

Basically your still going to have the same odds, it's just the OLL permutation is different than the PLL permutation, correct?
 
OMG this is the exact combination I just had yesterday in my record video!
http://www.youtube.com/watch?v=pfqs2rdAkRg#t=25
Still just coincidence.
Do yuo think that the distribution of the PLLs is independent of the OLL you are just executing?
Yeah. I'd summarize it like this:

PLL is affected, PLL probabilities are not.

QUOTE]

Just my thougt: A certain OLL gives the probabilities for the following PLLs. Those probabilities are not neccesarily the same as the known probabilities for the different PLLs. Weighting over all OLLs should give the correct value.
 
Just my thougt: A certain OLL gives the probabilities for the following PLLs. Those probabilities are not neccesarily the same as the known probabilities for the different PLLs. Weighting over all OLLs should give the correct value.

In this case, stop thinking and start doing math.
 
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