PatrickJameson
Premium Member
So in the past two days I've had three attempts at 4x4 bld. Two of which were a success. I do have to say that it has something to do with my center memo which I have not seen anyone do anything like this before. I will try to explain it the best I can but bear with me, it is a little hard to explain.
Ok, to start, we will label each center like so;
_____
|1|2|
|4|8|
The best way that I can explain this is with an example solve so here is a scramble: u L' R2 d r2 B f' L F' f2 d D' l' f' D' r' R D' F2 R' D2 r' d2 R' f2 F r2 L2 U B R' B b' R' l2 B' r d2 L' b2
I'll add a y2 since that seems to be the easiest. Note: I solve with White on top and Green in front.
So let's look at the U face. It has 3 pieces solved in the 1 2 and 4 position.
the first part of the memo would then be 1+2+4=7. What this number will do is tell us where the solved pieces are located. Do this for all of the sides going in the order of U F R B L D. You should have the memo sequence of 7 5 3 1 1 2.
Now for the actual memo. I always start with the U face as my buffer. I look at the first unsolved piece in the U face going in order of the 1 2 4 8 pieces. I see that the 8 piece is unsolved and has to go the the orange face which is L. L has a piece solved in the 1 position so we go to the 2 position. That is a yellow piece so it has to go to the D face. The D face has a piece solved in the 2 position so we look at the 1 position which is an orange piece so it has to go the the L face. Now, we already used the unsolved piece in 2 so we move on to position 4.
Got it so far?
Now, since we memoed where all the pieces are in the 7 5 3 1 1 2 sequence, we only need to memo the side the the piece is on. So to represent the visual memo that I would use, it would be U(buffer so not really needed), LDL, so far. If we continue this until all the pieces are accounted for it should be something like this; ULDLFB[end of cycle]FDLBRDF[end of cycle]RBR.
Ok, well there's bound to be something I missed so, tell me what you think
.
Ok, to start, we will label each center like so;
_____
|1|2|
|4|8|
The best way that I can explain this is with an example solve so here is a scramble: u L' R2 d r2 B f' L F' f2 d D' l' f' D' r' R D' F2 R' D2 r' d2 R' f2 F r2 L2 U B R' B b' R' l2 B' r d2 L' b2
I'll add a y2 since that seems to be the easiest. Note: I solve with White on top and Green in front.
So let's look at the U face. It has 3 pieces solved in the 1 2 and 4 position.
the first part of the memo would then be 1+2+4=7. What this number will do is tell us where the solved pieces are located. Do this for all of the sides going in the order of U F R B L D. You should have the memo sequence of 7 5 3 1 1 2.
Now for the actual memo. I always start with the U face as my buffer. I look at the first unsolved piece in the U face going in order of the 1 2 4 8 pieces. I see that the 8 piece is unsolved and has to go the the orange face which is L. L has a piece solved in the 1 position so we go to the 2 position. That is a yellow piece so it has to go to the D face. The D face has a piece solved in the 2 position so we look at the 1 position which is an orange piece so it has to go the the L face. Now, we already used the unsolved piece in 2 so we move on to position 4.
Got it so far?
Now, since we memoed where all the pieces are in the 7 5 3 1 1 2 sequence, we only need to memo the side the the piece is on. So to represent the visual memo that I would use, it would be U(buffer so not really needed), LDL, so far. If we continue this until all the pieces are accounted for it should be something like this; ULDLFB[end of cycle]FDLBRDF[end of cycle]RBR.
Ok, well there's bound to be something I missed so, tell me what you think