2x2x2

[MYKE]

can anyone give a decent web page telling me how to do a 2X2X2 cube please?

 

[John Lee]

You can solve a 2x2 if you know how to solve a 3x3.

heres the best site for 2x2
http://erikku.er.funpic.org/rubik/

 

[doubleyou]

the 2x2x2 was the last of the the series I learned.
I know what you are talking about.

for oll look at the corners and pick one of your algs for the 3x3x3 with the same corner situation. it works! then you just gotta find the shortest

for pll there are only two situations. A perm and Y perm. but you can use several other algs to fix it.

just play a little more with it after reading this, and see if you see what I mean.

 

[pjk]

For beginners, just solve one layer, then oriente the top, then permute the top. With that, you can avg around 6-9 seconds. If you want more advanced, check out Erik's site.

 

[Erik]

I've got also pretty basic method ther PJK

 

[pjk]

Yes, my bad. Check Erik's site for any 2x2 stuff

 

[Erik]

:lol:

 

[Mike Hughey]

If you already know Fridrich, it really makes a lot of sense to learn Ortega first (you can find it on Erik's site listed earlier). With Ortega, assuming you can get good enough on your own at making the first face (which is really pretty easy to do intuitively), you can just use your standard OLL corner algorithms for step 2 (to begin with - then you can learn the optimized ones to speed up a bit), and then if you use your standard PLL algorithms, you only have 3 new algorithms to learn for step 3 - and two of those are 7 moves and the third is just 3 moves! I just learned Ortega today, and it only took about 30 minutes to learn!

And it's a stepping stone to Guimond, in case you ever want to learn that.

 

[Lt-UnReaL]

I'm trying to learn Ortega on your site Erik(really nice site btw), but I don't think it has all the algs for step 3, every time I need to permute both layers it's always an alg that's not on there.

 

[sgowal]

Which case?

All the cases are there (and even more), you only need:
(RU2R'U')(RU2)(L'UR'U'L')
(FRU'R'U'RUR'F')(RUR'U')(R'FRF')
R2UR2' (U2 + y') R2UR2'
LD'L F2 L'DL
R2F2R2

 

[Mike Hughey]

Originally posted by Lt-UnReaL@Jul 3 2007, 06:16 PM
I'm trying to learn Ortega on your site Erik(really nice site btw), but I don't think it has all the algs for step 3, every time I need to permute both layers it's always an alg that's not on there.

That's what I thought when I first tried it, but in a way, the diagrams just make it look more complicated than it actually is. You really only need the first 6 algs (and one of them is do nothing!):

1. Two adjacent corners on one face need swapping
2. Two diagonally opposite corners on one face need swapping
3. Don't need to do anything!
4. Top layer has 2 adjacent corners that need swapping, and bottom layer also has 2 adjacent corners that need swapping. Line them up as shown and you're good to go.
5. I believe this algorithm is written wrong on Erik's site - I think it's supposed to be LD'L F2 L'DL' (there was a missing ' at the end). For this one, it's top layer has two opposite corners that need swapping, and bottom layer has 2 adjacent corners that need swapping. If you have the reverse (top are adjacent, bottom are opposite), just flip the cube.
6. Top and bottom layers both have 2 opposite corners that need swapping. Just line them up and go.

Remember that the goal here is really just to make the top and bottom faces correct. You still might have to turn the top layer to line them up when you're done.

That really does cover all possible cases. It's pretty neat how well it works.

 

[Erik]

ok I fixed the missing ' and also I made the recognition a bit more clear and updated one of the pictures to show the 2 bars don't have to match on the R2UR2U2 y R2UR2 case.

 

[Mike Hughey]

Thanks, Erik - I think the new description is very helpful.

 

[Lt-UnReaL]

Great. I'm learning this on my 4x4x4.

 

[AvGalen]

Erik, why don't you explain Ortega (final step) based on the number of horizontal bars?

0 bars: 6. Top and bottom layers both have 2 opposite corners that need swapping..
1 bar: 5. I believe this algorithm is written wrong
2 bars: 4. Top layer has 2 adjacent corners ...
4 bars: 2. Two diagonally opposite corners on one face need swapping
5 bars: 1. Two adjacent corners on one face need swapping
8 bars: 3. Don't need to do anything!