2x2 PLL probability

[Carlos]

Hey!

I'm kind of developing a 2x2 method, and I would like to know if any of you have done(or could do) the maths to find about the PLL probabilities at 2x2.

I want to know particularly if this case

happens more or less then the PLL skip, and in what proportion.

Thanks in advance.

 

[JustinJ]

They (it and the skip) both have the same probability, 1/6.

 

[Kenneth]

It's easy to count the cases, just look at the cube, there are 4 places where two adjacent corners can be swapped and two possibilitys for diagonal but "case II" can be transformed to "case I" using a U2 so they are both the same = 1 case. On top of that there is one situation with all corners correctly placed.

4 : adjacent swap
1 : diagonal swap
1 : solved
6 : total