JF1zl3
Veteran
Your method sounds like the 2 steps are tedious and highly intuitive, keyhole takes the pyraminx and breaks it into ~5 steps. And, obviously, the more steps, the less cases. Example on a 3x3x3:
Begginners method last layer: 4 steps, 14 cases (Step 1: 4 cases, Step 2: 3 cases, Step 3: 3 cases, Step 4: 4 cases)
One Look Last Layer: 1 Step, 1212 cases
The difference is clear. However there is a sort of an inverse relationship here. The more steps you have, the less cases, but the more cases you have the less steps. And obviously The outliers would be either too inefective (Begginner's) or take a long long time to handle it so well that it would actually impact your times (1LLL). So you have to find a balance between the two that leads to a low amount of steps and still maintain a reasonable amount of cases. Examples: PLL and OLL for the last layer, or 2-Look Last Layer, has 2 Steps and 80 cases. Is it THE best method for solving the last layer if you were the perfect cuber? No, that would be 1LLL, but you would have to completely learn that for it to be effective.
So to put this in terms of pyraminx, the balance I was referencing earlier between steps and cases is perfect for begginner to intermediate pyraminxers in the method of Keyhole. At least in my opinion.
Begginners method last layer: 4 steps, 14 cases (Step 1: 4 cases, Step 2: 3 cases, Step 3: 3 cases, Step 4: 4 cases)
One Look Last Layer: 1 Step, 1212 cases
The difference is clear. However there is a sort of an inverse relationship here. The more steps you have, the less cases, but the more cases you have the less steps. And obviously The outliers would be either too inefective (Begginner's) or take a long long time to handle it so well that it would actually impact your times (1LLL). So you have to find a balance between the two that leads to a low amount of steps and still maintain a reasonable amount of cases. Examples: PLL and OLL for the last layer, or 2-Look Last Layer, has 2 Steps and 80 cases. Is it THE best method for solving the last layer if you were the perfect cuber? No, that would be 1LLL, but you would have to completely learn that for it to be effective.
So to put this in terms of pyraminx, the balance I was referencing earlier between steps and cases is perfect for begginner to intermediate pyraminxers in the method of Keyhole. At least in my opinion.