Help with BLD corner Commutators

McWizzle94

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Hey everyone, I'm trying to learn corner commutators for BLD. So far, I know how to do most 3-cycles. The things I'm having trouble with are having to do pairs of 2 cycles and misoriented corners at the end. Could somebody please help me with this? Thanks
 
There's plenty of literature out there:

http://www.speedsolving.com/forum/showthread.php?t=169
intro to commutators in general

http://www.speedsolving.com/forum/showthread.php?t=697
intro to commutators for big cubes

If you understand commutators in general, and maybe see some examples for other piece types, then corners should make more sense.

Hope this helps,
Chris
Chris, thanks for the link, 4x4 center commutators are fun :)
I'm still a beginner but what ever.
Hopefully by Virginia I can do the 4x4 BLD
 
There's plenty of literature out there:

http://www.speedsolving.com/forum/showthread.php?t=169
intro to commutators in general

http://www.speedsolving.com/forum/showthread.php?t=697
intro to commutators for big cubes

If you understand commutators in general, and maybe see some examples for other piece types, then corners should make more sense.

Hope this helps,
Chris
Chris, thanks for the link, 4x4 center commutators are fun :)
I'm still a beginner but what ever.
Hopefully by Virginia I can do the 4x4 BLD

i had an interest in 4x4 BLD, but it didn't work too well xD. you can probably do a lot better.

anyway, thank you all for your help, but could anyone give a few examples solving the corners with commutators please? you don't need to add in edges though. thanks
 
Scramble: B' F2 R B2 F2 R' F D' B L2 R B' F' U' L2 R2 B' R2 U2 F' D F B2 U L2

I start from UFL, so the corners are: UFL->FLD->FRD->LBU->UFR->BUR->DRB->DLB

UFL->FLD->FRD: U' R U L' U' R' U L

UFL->LBU->UFR: y' R'2 D R' U2 R D' R' U2 R' y (set up with y' R2, cancellation in the end)

UFL->BUR->DRB: x' U L' U' R' U L U' R x

Then there's parity left.



Another scramble: D B2 L2 U' F' U R2 U' R D L2 D' U B2 F' D B2 F R2 L2 U F2 R' L F

UFL->UBL(break into new cycle)->URB->DLF->BLD:p->FUR->FRD->BRD->BUR

UFL->UBL->URB: (A-perm: x L2 D2 L' U' L D2 L' U L' x')

UFL->DLF->BLD: you can do D to make it an A-perm on the F-face, which is IMO the fastest solution for this case. But this is a shorter solution: D' L2 D' R' D L2 D' R D2 (D' is set up, and there is a cancellation in the end)

UFL->FUR->FRD: Again you can set it into A-perm (with R). Shorter solution: R' F2 R' B' R F2 R' B R2 (set up with R, cancellation in the end)

UFL->BRD->BUR: x' R D2 R' U' R D2 R' U x, or again you could set up into A-perm, with R'.

I hope this helps.
 
Scramble: B' F2 R B2 F2 R' F D' B L2 R B' F' U' L2 R2 B' R2 U2 F' D F B2 U L2

I start from UFL, so the corners are: UFL->FLD->FRD->LBU->UFR->BUR->DRB->DLB

UFL->FLD->FRD: U' R U L' U' R' U L

UFL->LBU->UFR: y' R'2 D R' U2 R D' R' U2 R' y (set up with y' R2, cancellation in the end)

UFL->BUR->DRB: x' U L' U' R' U L U' R x

Then there's parity left.



Another scramble: D B2 L2 U' F' U R2 U' R D L2 D' U B2 F' D B2 F R2 L2 U F2 R' L F

UFL->UBL(break into new cycle)->URB->DLF->BLD:p->FUR->FRD->BRD->BUR

UFL->UBL->URB: (A-perm: x L2 D2 L' U' L D2 L' U L' x')

UFL->DLF->BLD: you can do D to make it an A-perm on the F-face, which is IMO the fastest solution for this case. But this is a shorter solution: D' L2 D' R' D L2 D' R D2 (D' is set up, and there is a cancellation in the end)

UFL->FUR->FRD: Again you can set it into A-perm (with R). Shorter solution: R' F2 R' B' R F2 R' B R2 (set up with R, cancellation in the end)

UFL->BRD->BUR: x' R D2 R' U' R D2 R' U x, or again you could set up into A-perm, with R'.

I hope this helps.

Thank you very much for your help!!!!! I really appreciate it!
 
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