miniGOINGS
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- Feb 27, 2009
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I think the OLL parity is caused by an odd number of twists in the inner layers like Rw..
Can somebody tell me, is this true?
Yes.
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I think the OLL parity is caused by an odd number of twists in the inner layers like Rw..
Can somebody tell me, is this true?
I think the OLL parity is caused by an odd number of twists in the inner layers like Rw..
Can somebody tell me, is this true?
I have a question:
Do you use K4?
I don't think this should be still considered parity as in all actuality at least 2 centers need to be rotated. One of the centers just has to be trivially rotated along with the piece that needs solving.So... center orientation parity?Fisher Cube doesn't have parity, it only has rotated centers like a picture cube would have.
I have never looked into the inner workings of sq-1 parity, so my original statement stands. I seem to understand it a little now, based off of chris's explanation of the corners just being bandaged edges.Not even the setup-to-turn-six-corners solution?I personally still don't get how sq-1 parity works
I have a question:
Do you use K4?
As you still seem to be oblivious to the hilarity, let me spell it out for you.
Kirjava invented it. :O
And how do you know that? That you can't just rotate one center alone (by 90 degrees)?I don't think this should be still considered parity as in all actuality at least 2 centers need to be rotated. One of the centers just has to be trivially rotated along with the piece that needs solving.
I guess what he was saying was that you don't need to know whether that's possible. Even if the 3x3 did have a center orientation parity issue, where one could be 90 degrees off, you wouldn't have to be able to solve that for a Fisher Cube because the two-center-twist commutator is intuitive/straightforward and would fix that problem. So it's not really right to call it a parity, just a tricky situation that is part of the puzzle, when the solution is just a matter of realizing you can do a commutator on a piece you want solved and a piece that doesn't show orientation.And how do you know that? That you can't just rotate one center alone (by 90 degrees)?I don't think this should be still considered parity as in all actuality at least 2 centers need to be rotated. One of the centers just has to be trivially rotated along with the piece that needs solving.
That is very vague and almost false.Square-1 parity happens i think because of an odd permutation occuring outside of cube shape, so when you get it back to cube shape you get parity.
Void cube doesn't have centres.void cube, parity happens because the centres can be changed
No.4x4 because centres can be changed as well (at least this causes permutation parity i think)
Fisher cube does have parity. You get a edge orientation parity when trying to solve the top cross if one of the edges with no obvious orientation is flipped.Fisher Cube doesn't have parity, it only has rotated centers like a picture cube would have.
Michael described them very well in his post, so there is no need to redo it.
Chris
Michael described them very well in his post, so there is no need to redo it.
Chris
Can you please direct me to his post? I'm really curious about square-1 parity.
Post #44 in this thread.