cmhardw
Premium Member
Yes that's freestyle conjugates not commutators.
I've been thinking about alternative methods for 2x2x2 BLD, or at least more advanced techniques to supplement the existing ones.
My thinking is that the algorithm U (yes turning the U layer once clockwise) is a very useful 4-cycle, and that U2 (turn the U layer twice) is a very useful way to perform 2 double swaps.
Now the problem comes in with setting up the 4 corners you need onto one layer in such a way as to accomodate a 4-cycle or a double 2-swap whichever is needed. But I did notice that sometimes the setups aren't really that bad. This could be a useful trick I think, on some easy cases.
I have started practicing sighted solves this way, I'm not brave enough to try it in a real BLD solve yet. Anyway I thought it was interesting, and I only really plan to apply this to 2x2x2 BLD, which I seriously doubt will ever make it to WCA approved event status, but still it is fun to try.
Here is an example solve to further explain what I mean with this:
scramble: B2 U2 R2 B2 U B' D' F' L2 B U2 L' U' L' B'
cycles as I see them: UBL->LDF->BRD->BDL->RBU->RUF->RFD->ULF->UBL
The first 4 of this can be setup into a 4cycle on the U layer with: F2 D' F' R D R'
Now do U' to perform the 4 cycle
now undo with: R D' R' F D F2
the next 4 can also be made into a 4 cycle by doing: D L' D'
now perform the 4 cycle with: R'
now undo the setup with: D L D'
this leaves the last two corners to be swapped with your favorite PLL alg, I use T perm: L' U' L U L F' L2 U L U L' U' L F
This solve was not fabricated, I got the scramble from JNetcube, but I feel that this is unusually easy for a solve of this nature. Of the solves I've tried so far I have yet to do one with 2 easy 4 cycles like this. Still, it is good for demonstration purposes, even though I feel it does not represent in the best way how I feel these "tricks" can be used realistically in a solve.
Chris
I've been thinking about alternative methods for 2x2x2 BLD, or at least more advanced techniques to supplement the existing ones.
My thinking is that the algorithm U (yes turning the U layer once clockwise) is a very useful 4-cycle, and that U2 (turn the U layer twice) is a very useful way to perform 2 double swaps.
Now the problem comes in with setting up the 4 corners you need onto one layer in such a way as to accomodate a 4-cycle or a double 2-swap whichever is needed. But I did notice that sometimes the setups aren't really that bad. This could be a useful trick I think, on some easy cases.
I have started practicing sighted solves this way, I'm not brave enough to try it in a real BLD solve yet. Anyway I thought it was interesting, and I only really plan to apply this to 2x2x2 BLD, which I seriously doubt will ever make it to WCA approved event status, but still it is fun to try.
Here is an example solve to further explain what I mean with this:
scramble: B2 U2 R2 B2 U B' D' F' L2 B U2 L' U' L' B'
cycles as I see them: UBL->LDF->BRD->BDL->RBU->RUF->RFD->ULF->UBL
The first 4 of this can be setup into a 4cycle on the U layer with: F2 D' F' R D R'
Now do U' to perform the 4 cycle
now undo with: R D' R' F D F2
the next 4 can also be made into a 4 cycle by doing: D L' D'
now perform the 4 cycle with: R'
now undo the setup with: D L D'
this leaves the last two corners to be swapped with your favorite PLL alg, I use T perm: L' U' L U L F' L2 U L U L' U' L F
This solve was not fabricated, I got the scramble from JNetcube, but I feel that this is unusually easy for a solve of this nature. Of the solves I've tried so far I have yet to do one with 2 easy 4 cycles like this. Still, it is good for demonstration purposes, even though I feel it does not represent in the best way how I feel these "tricks" can be used realistically in a solve.
Chris
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