trying-to-speedcube...
Veteran
So I've been thinking about a method to solving in the [R, U]-group.
So first, theory: what is possible, what isn't?
Possible:
-5-cycles of corners
-2 2-cycles of corners*
-3-cycles of edges
-2 2-cycles of edges
-2 3-cycles of corners
-2-cycle of edges+4-cycle of corners (parity)
Impossible:
-3-cycles of corners
-Edge orientation
-2-cycle of edges+2-cycle of corners
So this is a pretty hard one.
Orientation:
Edges: -
Corners: U'RUR'URU2R'U2R'U'RU'R'U2RU' and its inverse
Permutation:
Edges: Pretty straight-forward: edge-PLL's with setups
Corners: I think this is the hardest part, with CE i found a double 2-cycle:
R2 U2 R' U2 R2 U2 R2 U2 R' U2 R2 U2, or any RU H-perm+U2 for that matter...
5-cycle: R2 U' R2 U R2 U' R2 U R2 U' R2 U (1-3-7-4-8)
5-cycle: R U2 R2 U2 R U' R' U' R2 U R' U (1-7-8-3-4)
If you know more algs, let me know!
*Why is an H-perm possible, while an E-perm isn't?
Tell me what you think
So first, theory: what is possible, what isn't?
Possible:
-5-cycles of corners
-2 2-cycles of corners*
-3-cycles of edges
-2 2-cycles of edges
-2 3-cycles of corners
-2-cycle of edges+4-cycle of corners (parity)
Impossible:
-3-cycles of corners
-Edge orientation
-2-cycle of edges+2-cycle of corners
So this is a pretty hard one.
Orientation:
Edges: -
Corners: U'RUR'URU2R'U2R'U'RU'R'U2RU' and its inverse
Permutation:
Edges: Pretty straight-forward: edge-PLL's with setups
Corners: I think this is the hardest part, with CE i found a double 2-cycle:
R2 U2 R' U2 R2 U2 R2 U2 R' U2 R2 U2, or any RU H-perm+U2 for that matter...
5-cycle: R2 U' R2 U R2 U' R2 U R2 U' R2 U (1-3-7-4-8)
5-cycle: R U2 R2 U2 R U' R' U' R2 U R' U (1-7-8-3-4)
If you know more algs, let me know!
*Why is an H-perm possible, while an E-perm isn't?
Tell me what you think